c++

ROBERT

#include , N, Z9 E' S( P# X6 yvoid index(int a[];int n;int ⊂) { 3 M" m e: T3 V% [/ n( Yint i ; $ h/ ]; t! D' R B) U7 U7 nfor (i=0;i<=n;i++；) {if( a=&sub)&sub=i;} 3 `* E' I. \; l3 Y% l9 z( F5 M6 o if (i>n)&sub=-1; ( {$ I7 C, e# S% ?} $ f- e, i- R" C* R* Z+ _void main () { int g,i,m,h; ) U5 }; N7 `$ ^" Q6 N! { printf("数组个数为：\n"); scanf("%d",&g); 1 w. {& ^% U, p( p* Y- {: U9 ]int b[g]; # j5 L( h3 Z* y8 P! J: j: sprintf("请输入%d个整数：\n",g); / B X8 J7 o9 d& F: N3 J z/ \3 nfor (i=0;i<=g;i++;) 9 |" |, a2 f* r* X8 pb=scanf("%d",m); * r9 {6 m! Y y0 L! v2 j printf("要查找的数为：\n"); scanf("%d",&h); index(b[g],g,h); ! {( G; ~8 @. ?, @$ T8 {! ^if(h=-1)printf("该数组中有 %d\n",h); else if (h!=-1)printf("该数组中没有 %d\n",h); }

ROBERT

#include<iostream.h> #include<math.h> - a/ s @+ U- ?& M; M5 [, e double area(double radius=0){ double s ; s=radius*radius*3.14; return(s); 5 T1 R+ y0 k4 J! z7 ~}

double area(double a=0,double b=0) 2 z8 m, L2 n& j( f7 K) L { % ^. t( ~- t% f# D double s; s=a*b; return(s); 2 Y" T0 Z( J p3 J* d } ( [" y4 F! \% [3 M, h5 }5 Tvoid main(){ 8 E3 v h! t4 vdouble s1,s2,s3,s4,r,a,b; cout<<"圆的半径为："; g* A+ ^: O1 ]+ j cin>>r; ) x# D. F4 r7 d9 m7 i! @: V o s1=area(r); cout<<"圆的面积为："<<s1<<endl; cout<<"矩形的长为："; 1 n/ L1 g5 f- D/ M, h cin>>a; cout<<"矩形的宽为："; ; _+ }3 }- \: B) u cin>>b; s2=area(a,b); cout<<"矩形的面积为："<<s2<<endl;

& m8 [2 y; q- Y+ H}

游侠无极限

？我认为你用的变量太多了……

发这个干什么？

游侠无极限

本来想写个试试，可为什么Dev-cpp会提示我Rectangle未定义？奇怪

VC7就很顺利？

#include <iostream> #include <stdlib.h>

#define PI 3.14 : r4 b# p! M% j" x) a/ iusing namespace std;

class Shape ) Y7 \$ K: `/ z" s0 y; {{ 7 u& { M- u$ f3 S- M5 W1 Vprivate: * X. W' ~+ u1 r$ n/ K* p double m_width; double m_height; public: Shape(){}; ~Shape(){}; 6 C" Q& Y/ o z7 V void SetWidth(double w = 0){m_width = w;}; 4 @: ?' V& u* }; _, B void SetHeight(double h = 0){m_height = h;}; double GetWidth(void){return m_width;}; double GetHeight(void){return m_height;}; virtual double GetArea(void) = 0; };

class Rectangle : public Shape { public: Rectangle(){}; ~Rectangle(){}; virtual double GetArea(void){return GetWidth()*GetHeight();}; ; z- A8 F2 J6 x8 B, M! N" K};

class Circle : public Shape 8 r% M* a* m2 g8 T$ C: K; s{ ! z+ [; A8 U, @9 n6 a1 _% Zpublic: 9 C8 l. t! ?! U+ g' V: ^ Circle(){}; 3 r3 K% c6 g. Q' N* _* Y+ a ~Circle(){}; virtual double GetArea(void){return GetWidth()*GetWidth()*PI;}; void SetRadius(double r = 0){SetWidth(r);};

};

// ------------------------------------------------ // 主函数过程 // ------------------------------------------------ 3 q8 u1 ^/ i9 ] o* L7 ~int main(int argc, char *argv[]) # P4 g: r _2 u7 P6 h4 j/ o3 \{ + N \$ Z4 L6 I4 R, g2 ~+ n; Q9 P Rectangle re;

Circle ci; Shape *p1 = &re,*p2 = &ci; ! Q% k6 ?. p1 P7 X, c ? re.SetHeight(20); - V5 X# W, D) K) S) f5 | re.SetWidth(10); ) a; @! `) R* t3 f) n ci.SetRadius(12); & m$ {, o7 O5 }8 z2 l0 J, I cout << "矩形面积：" << p1->GetArea() << endl; cout << "圆形面积：" << p2->GetArea() << endl;

system("PAUSE"); ( F O4 S r- ~. ^& Q; o return 0; 9 k1 _6 k% W/ P3 Z) l$ p}