谁帮我看看这代码错在哪，顺便改下。。谢谢

baobao1987

<% //String servletPath=request.getServletPath();  
/ q3 d  {) \4 l! R4 |! z) s. T   // int end =servletPath.lastIndexOf('/')+1;
//System.out.println(end);
0 c5 D! Y6 v: m+ y; X4 ^0 q( m //String photoPath=servletPath.substring(0,end);
' E* x+ z9 d# f2 G1 }6 e3 k String path=request.getRequestURI();
4 M  s! d% [# S( a6 W: c //System.out.println(path);
, j* h; h- `" {  T) b7 B/ v% X int end =path.lastIndexOf('/')+1;
String photoPath=path.substring(0,end);
System.out.println(photoPath);
%>
. ^& Q3 Z# ~7 R+ m<script language="javascript">
function showPic(obj) {
6 e- l% k; @& M( e/ H  var o = document.getElementById("showimg");
1 F8 c! H4 R5 E: m) V  I" U; Y' @- u  var b = document.getElementById("photoPath");
  var i=obj.value.lastIndexOf('s')+2;
# ~+ w( v5 Q) ]! z* h8 @' I6 g  var j=obj.value.length;
  //var a = document.image.value;
% ~) ]; p* h9 q4 F( ]- ?  //var int j=a.length;
" T% I+ y0 t3 N/ I8 x; e! P  //var i=a.lastIndexOf('s')+2;
  var filename=obj.value.substring(i,j);
  o.src=b.value+"images/"+filename;
  o.style.display="";
$ W6 l6 T6 v- I+ o! M$ a  o.border=1;
}
- u/ o2 ~( a: `1 k& P! l# x* E% u</script>
<form>
8 b" B2 v4 k9 f- l8 U; t<input name="image" type="file" id="image" size="50" >
2 Q6 j6 g( _0 B9 k* h; j<div align="center"><img name="showimg" id="showimg" src="" style="display:none;" alt="预览图片" /></div>
</form>

xh1123

这样谁看得出来哦，把整个文件贴出来。。。看看 ，，呵呵

8760747

怎么也得把错误的信息发来吧
# S) I& v8 Y. w! j0 s/ X' b6 a! @这样能帮你看看